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777dan777 [17]
4 years ago
7

Explain, in terms of both atoms and molecular structure, why there is no isomer of CH3OH.

Chemistry
1 answer:
Jet001 [13]4 years ago
5 0

Explain, in terms of both atoms and molecular structure, why there is no isomer of CH3OH.

There is no isomer of CH3OH or methanol because it contains only one carbon atom. And also, the structure is tetrahedral, having four substances attached to the carbon atom.

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Study island help pleaseeee
yaroslaw [1]

Answer:

A or D should be the answer

8 0
3 years ago
Read 2 more answers
Consider this equilibrium reaction between carbon monoxide and hydrogen gas, occurring in a sealed flexible container. CO(g) + 3
wariber [46]

Answer:

More H2(g) is added to the container : <u>Towards products.</u>

CO is removed from the container : <u>Towards reactants.</u>

More CH4(g) is added to the container : <u>Towards reactants</u>

H2O(g) is removed from the container <u>: Towards products.</u>

The contents of the container are heated up. :<u> Towards the reactants.</u>

The contents of the container are cooled down : <u>Towards the products.</u>

The pressure inside the container is increased. :<u>Towards the products</u>

The container is stretched to increase the volume: <u>Towards the reactants.</u>

Explanation: :

CO(g) + 3 H2g) → CH4(g) + H2O(g)+ heat

There is released heat, so this reaction is exothermic

If the H2 concentration is increased, the system will try to change the concentration change by shifting the balance to the right, and thus the concentration of products will increase.<u> Towards products.</u>

If the CO is removed, the system will try to change this situation by shifting the balance to the left, and thus the concentration of reactants will increase, the concentration of products will decrease. <u>Towards reactants.</u>

If the CH4 concentration is increased, the system will try to change the concentration change by shifting the balance to the left, and thus the concentration of reactants will increase. <u>Towards reactants</u>

If the H2O is removed, the system will try to change this situation by shifting the balance to the right, and thus the concentration of products will increase, the concentration of products will decrease. <u>Towards products.</u>

If the temperature is increased, the system will reduce the amount of heat released. So the balance will shift to the left. <u>Towards the reactants.</u>

This because the extra heat / energy must be used.

If the temperature is decreased, the system will produce more heat  So the balance will shift to the right. <u>Towards the products.</u>

This because more heat /energy needs to be produced to make up for the loss of heat (energy).

If the pressure is increased, the system will shift to the side with fewer moles of gas. In this case, there are 4 moles on the left and 2 moles on the right.  So the balance will shift to the right. <u>Towards the products.</u> An increase of pressure has the same effect on the equilibrium as a decrease of the volume.

If the volume is increased, this means the pressure is decreased, the system will shift to the side with most moles of gas. In this case, there are 4 moles on the left and 2 moles on the right.  So the balance will shift to the left. <u>Towards the reactants.</u> An increase of volume has the same effect on the equilibrium as a decrease of the pressure.

6 0
4 years ago
Calculate the density of a sample of gold if the sample has a volume of 48.9cm3 and a mass of 944.75 g
LekaFEV [45]

Answer:

19.3g/cm^3

Explanation:

Hey,

the formula for density is Mass/Volume so in this question you basically put the given things in the formula

D = M/V

D= 944.75/48.9

D= 19.3g/cm^3

7 0
3 years ago
Read 2 more answers
How many different elements are involved in the reaction shown below?
Alborosie

Answer:

4

Explanation:

Cu, SO Na NO

3 0
4 years ago
A solution was prepared by mixing 50.0 g
frez [133]

Answer:

4.78 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em></em>

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

<em>∴ mass % = (mass of solute/mass of solution) x 100</em> = (50.0 g/1047.0 g) x 100 = <em>4.776 % ≅ 4.78 %.</em>

4 0
4 years ago
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