<span>3-Methylbutyl propanoate can be synthesized by reacting Propionic Acid with 3-Methylbutanol in the presence of Acid. This reaction is called as Esterification. The synthesis of
</span><span>3-Methylbutyl propanoate is shown below,</span>
Answer:
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Explanation:
Explanation:
This is a neutral beryllium atom
Answer:
D. Is the correct Option!
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<u><em>Hope this helps!!! :)</em></u>
Answer:
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Explanation:
<u>1. Chemical balanced equation (given)</u>

<u>2. Mole ratio</u>

This is, 1 mol of NaOH will reacts with 1 mol of KHP.
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<u>3. Find the number of moles in 72.14 mL of the base</u>



<u>4. Find the number of grams of KHP that reacted</u>
The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol
Convert moles to grams:
- mass = number moles × molar mass = 0.007055mol × 204.23g/mol
You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).
<u>5. Find the percentage of KHP in the sample</u>
The percentage is how much of the substance is in 100 parts of the sample.
The formula is:
- % = (mass of substance / mass of sample) × 100
- % = (1.4408g/ 1.864g) × 100 = 77.3%