gravitational potential is directly proportional to the height of the object relative to a reference line and is given as
PE = mgh
where m = mass of object , g = acceleration due to
gravity and h = height of the object above the reference line .
as the skydiver falls , its height above the ground decrease and hence the gravitational potential energy of the skydiver decrease.
as per conservation of energy , total energy of the skydiver must remain constant all the time . hence the decrease in potential energy appears as increase in kinetic energy by same amount to keep the total energy constant
KE + PE = Total energy
so as the skydiver falls , it gains speed and hence the kinetic energy of skydiver increase since kinetic energy is directly proportional to the square of the speed.
when the parachute opens, the skydiver experience force in upward which tries to balance the weight of the skydiver. hence the speed of the skydiver decrease until upward force becomes equal to the downward force. hence the kinetic energy decrease just after the parachute opens
Answer:

Explanation:
We can calculate the acceleration experimented by the passenger using the formula
, taking the initial direction of movement as the positive direction and considering it comes to a rest:

Then we use Newton's 2nd Law to calculate the force the passenger of mass m experimented to have this acceleration:

Which for our values is:

The average speed between 0 h and 2.340 h is 6.97 Km/h
Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.

With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:
- Total time = 2.340 – 0 = 2.340 h
- Total distance = 16.3 – 0 = 16.3 Km
- Average speed =?

Learn more about average speed: brainly.com/question/24884027
Explanation:
It is given that,
Input voltage, 
Input current, 
Output current, 
Number of turns in the secondary side of transformer, 
We need to find the number of turns in the primary side of the transformer. The current to the number of turns in the input and output is given by :

Substituting all the above values
So,

So, the number of turns in primary side of the transformer is 5885.
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