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Alexxx [7]
3 years ago
8

400cm³ of dry air was passed over heated copper powder in a hard glass tube until no further change. What volume of remained at

the end of the experiment?​
Chemistry
2 answers:
Ne4ueva [31]3 years ago
5 0

Answer:320cm³

Explanation:

20% of oxygen is present in 100% of air

xcm³ of O2 is present in 400cm³ of air

Therefore

80cm³ of O2 is present in 400cm³ of air

Vol of air remained =400-80

=320cm³ of air

2Cu+O2=>2CuO

2mol. 1mol. 2mol

160cm³. 80cm³ 160cm³

Since O2 is used up in the reaction

Vol of air remained=320cm³

Mark please

Delicious77 [7]3 years ago
3 0

Explanation:

I think there' will be a decrease in volume of the air.

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4 years ago
Now we need to find the amount of NF3 that can be formed by the complete reactions of each of the reactants. If all of the N2 wa
Alex777 [14]

The question is incomplete, the complete question is:

Nitrogen and fluorine react to form nitrogen fluoride according to the chemical equation:

N_2(g)+3F_2(g)\rightarrow 2NF_3(g)

A sample contains 19.3 g of N_2 is reacted with 19.3 g of F_2. Now we need to find the amount of NF_3 that can be formed by the complete reactions of each of the reactants.

If all of the N_2 was used up in the reaction, how many moles of NF_3 would be produced?

<u>Answer:</u> 1.378 moles of NF_3 are produced in the reaction.

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

In the given chemical reaction, N_2 is considered as a limiting reagent because it limits the formation of the product and it was completely consumed in the reaction.

We are given:

Mass of N_2 = 19.3 g

Molar mass of N_2 = 28.02 g/mol

Putting values in equation 1:

\text{Moles of }N_2=\frac{19.3g}{28.02g/mol}=0.689mol

For the given chemical reaction:

N_2(g)+3F_2(g)\rightarrow 2NF_3(g)

By the stoichiometry of the reaction:

1 mole of N_2 produces 2 moles of NF_3

So, 0.689 moles of N_2 will produce = \frac{2}{1}\times 0.689=1.378mol of NF_3

Hence, 1.378 moles of NF_3 are produced in the reaction.

8 0
3 years ago
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Answer:

This question is asking to find the average speed during the dive. The answer is 22m/s.

Explanation:

Average speed of a substance can be calculated knowing it's distance over a particular amount of time.

The formula for average speed is:

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In the case of this question where A peregrine falcon dives 176 meters through the air in 8 seconds, the distance of the falcon is 176m, while the time is 8s. Hence;

Average speed = 176/8

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Therefore, the average speed of the falcon diver is 22m/s.

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