Answer:
Solution's mass = 200.055 g
[PbSO₄] = 275 ppm
Explanation:
Solute mass = 0.055 g of lead(II) sulfate
Solvent mass = 200 g of water
Solution mass = Solvent mass + Solution mass
0.055 g + 200 g = 200.055 g
ppm = μg of solute / g of solution
We convert the mass of solute from g to μg
0.055 g . 1×10⁶ μg/ 1g = 5.5×10⁴μg
5.5×10⁴μg / 200.055 g = 275 ppm
ppm can also be determined as mg of solute / kg of solution
It is important that the relation is 1×10⁻⁶
Let's verify: 0.055 g = 55 mg
200.055 g = 0.200055 kg
55 mg / 0.200055 kg = 275 ppm
A gas has more free molecules, and it is air, not a tangible substance. Hope it helps! :)
Answer:
The period 2 element would be more reactive because the attractive force of protons is stronger when electrons are attracted to a closer electron shell.
Explanation:
Nonmetals want to add more electrons to their valence electron shell. Elements in period 2 have their valence shell closer their nucleus, then they are more reactive than period 4 elements.
Answer : The molar solubility of 
is 
Explanation :
The solubility equilibrium reaction will be:
The expression for solubility constant for this reaction will be,
Let the molar solubility be, 'x'
Now put all the given values in this expression, we get:
Therefore, the molar solubility of is
