We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).
Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).
To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
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Answer:
The molar mass and molecular weight of Al(CH3CO2)3 is 204.1136.
Explanation:
C) elements from the top left and the top right of the periodic table
Answer:
D. 1
Explanation:
Hydrogen is the chemical element with the symbol H and atomic number 1. With a standard atomic weight of 1.008, hydrogen is the lightest element in the periodic table. Hydrogen is the most abundant chemical substance in the Universe, constituting roughly 75% of all baryonic mass.
Answer:
Q = ne
Explanation:
Ler n be the number of electrons transferred and Q be the charge of an ion.
The net charge on the object is then given by :
Q = ne
Where
e is the electronic charge
Hence, the charge of an ion relates to the number of electrons transferred is equal to Q = ne.
