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Alexxx [7]
3 years ago
8

400cm³ of dry air was passed over heated copper powder in a hard glass tube until no further change. What volume of remained at

the end of the experiment?​
Chemistry
2 answers:
Ne4ueva [31]3 years ago
5 0

Answer:320cm³

Explanation:

20% of oxygen is present in 100% of air

xcm³ of O2 is present in 400cm³ of air

Therefore

80cm³ of O2 is present in 400cm³ of air

Vol of air remained =400-80

=320cm³ of air

2Cu+O2=>2CuO

2mol. 1mol. 2mol

160cm³. 80cm³ 160cm³

Since O2 is used up in the reaction

Vol of air remained=320cm³

Mark please

Delicious77 [7]3 years ago
3 0

Explanation:

I think there' will be a decrease in volume of the air.

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Acid strength in a series of h−a molecules increases with increasing size of
-BARSIC- [3]
Hello there!

The statement that Acid strength in a series of H-A molecules increases with increasing size of A is True.

When only the size is involved, increasing the size will increase the Acid strength because as size increases, the H-A bond will become weaker as the atoms will be farther apart. Acid strength is related to the ability to release H⁺ ions and a weaker H-A bond will release H⁺ more easily. 

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8 0
3 years ago
When steam condenses into water, __________. When steam condenses into water, __________. heat is given off by the water no heat
lys-0071 [83]

Answer: heat is given off by the water

Explanation:

Condensation can be defined as the process by which water vapors or steam in the atmosphere are converted into liquid water. It is the part of water cycle. The water form water bodies and terrestrial surfaces gets evaporated in the form of water vapors. These vapors rise in the upper atmospheric layers and aggregate to form the clouds when these vapors become heavy they fall down in the form of rain. Heat is given off in this process by the water vapors or steam to be converted in liquid.

4 0
3 years ago
I need help with Chemistry: Mole Conversion<br> It must be answered in complete detail
Anni [7]

Answer:

As Per Given Information

Number of moles SO₂ ( Sulphur dioxide ) is 0.30

We 've been asked to find the number of atoms in given moles of Sulphur dioxide .

Value of Avogadro Number is 6.022 × 10²³ mol⁻¹

For finding the number of atoms we will use formale

\underline{\boxed{\textbf{\textsf{ Number \: of \: atoms \:  = Given \: moles \:  . Avogadro \: number}}}}

Putting the given value we obtain

\sf \twoheadrightarrow \: Number \: of \: atoms \:  = 0.30 \times 6.022 \times  {10}^{  23}    \\  \\ \sf \twoheadrightarrow \: Number \: of \: atoms \:  = \: 1.8066 \times  {10}^{ 23} atoms

So, the number of atoms in sulphur dioxide is 1.8066 × 10²³

8 0
2 years ago
The rate constant for the reaction 3A equals 4b is 6.00×10 how long will it take the concentration of a to drop from 0.75 to 0.2
Lelu [443]

This question is incomplete, the complete question is;

The rate constant for the reaction 3A equals 4B is 6.00 × 10⁻³ L.mol⁻¹min⁻¹.

how long will it take the concentration of A to drop from 0.75 to 0.25M ?

from the unit of the rate constant we know it is a second reaction order

OPTIONS

a) 2.2×10^−3 min

b) 5.5×10^−3 min

c) 180 min

d) 440 min

e) 5.0×10^2 min

Answer:

it will take 440 min for the concentration of A to drop from 0.75 to 0.25M

Option d) 440 min is the correct answer

Explanation:

Given that;

Rate constant K =  6.00 × 10⁻³ L.mol⁻¹min⁻¹

3A → 4B

given that it is a second reaction order;

k = 1/t [ 1/A - 1/A₀]

kt = [ 1/A - 1/A₀]

t = [ 1/A - 1/A₀] / k

K is the rate constant(6.00 × 10⁻³)

A₀ is initial concentration( 0.75 )

A is final concentration(0.25)

t is time required = ?

so we substitute our values into the equation

t = [ (1/0.25) - (1/0.75)] / (6.00 × 10⁻³)

t = 2.6666 / (6.00 × 10⁻³)

t = 444.34 ≈ 440 min     {significant figures}

Therefore it will take 440 min for the concentration of A to drop from 0.75 to 0.25M

Option d) 440 min is the correct answer

6 0
3 years ago
The formula for lithium oxide is A) Li2O B) LiO2 C) LiO D) Li2O3
Greeley [361]
Li2O is the formula for <span> lithium oxide</span>
4 0
3 years ago
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