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rodikova [14]
3 years ago
5

The spraying of pesticides can be carefully planned, but accidents, weather conditions that could not be foreseen, and pilot err

ors often cause much larger deposits of spray than they had anticipated.(A) weather conditions that could not be foreseen, and pilot errors often cause much larger deposits of spray than they had(B) weather conditions that cannot be foreseen, and pilot errors often cause much larger deposits of spray than(C) unforeseeable weather conditions, and pilot errors are the cause of much larger deposits of spray than they had(D) weather conditions that are not foreseeable, and pilot errors often cause much larger deposits of spray than(E) unforeseeable weather conditions, and pilot errors often cause much larger deposits of spray than they had
Physics
1 answer:
12345 [234]3 years ago
6 0

Answer:

B) weather conditions that cannot be foreseen, and pilot errors often cause much larger deposits of spray than

Explanation:

Option B obeys the principle of parallelism because the two phrases, " can be carefully planned" and "cannot be foreseen" follow the same grammatical structure. Option A does not obey parallelism because " can be carefully planned" and "could not be foreseen" do not follow the same grammatical structure.

The phrase " they had anticipated" in the other options apart from B do not have a matching subject. Pilot errors is the subject in this sentence and it is not expected to anticipate anything, only the pilots can.

Moreover, "that cannot be foreseen" is more parallel to "can be carefully planned" that "unforeseeable" or "foreseeable" used in the other options

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it is about 384,750 kilometers from earth to the moon. it took the apollo astronauts about 2 days and 19.5 hours to fly to the m
Jet001 [13]
We know, speed = Distance / Time
d = 384,750 Km
t = 2 days, 19.5 hours = 48+19.5 = 67.5 hour

Substitute their values, 
s = 384,750 / 67.5
s = 5700 Km/h

In short, Your Answer would be 5700 Km/h

Hope this helps!
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3 years ago
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A 1500 kg car traveling 5.0 m/s collides head on with a 3000 kg truck traveling
Setler [38]
  • m1=1500kg
  • m_2=3000kg
  • v_1=5m/s
  • v_2=7m/s

Using law of conservation of momentum

\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3

\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3

\\ \sf\Rrightarrow 7500-21000=4500v_3

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Using energy considerations, calculate the average force (in N) a 67.0 kg sprinter exerts backward on the track to accelerate fr
Illusion [34]

Answer:

F_{sprinter}=110.4N

Explanation:

Given data

Mass m=67.0 kg

Final Speed vf=8.00 m/s

Initial Speed vi=2.00 m/s

Distance d=25.0 m

Force F=30.0 N

From work-energy theorem we know that the work done equals the change in kinetic energy

W=ΔK=Kf-Ki=1/2mvf²-1/2mvi²

And

W=F_{total}.d

So

W=1/2mv_{f}^2-1/2mv_{i}^2\\F_{total}=\frac{1/2mv_{f}^2-1/2mv_{i}^2}{d} \\F_{total}=\frac{1/2(67.0kg)(8.00m/s)^2-1/2(67.0kg)(2.00m/s)^2}{25.0m} \\F_{total}=80.4N

and we know that the force the sprinter exerted Fsprinter the force of the headwind Fwind=30.0N

So

F_{sprinter}=F_{total}+F_{wind}\\F_{sprinter}=80.4N+30N\\F_{sprinter}=110.4N  

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3 years ago
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