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rodikova [14]
3 years ago
5

The spraying of pesticides can be carefully planned, but accidents, weather conditions that could not be foreseen, and pilot err

ors often cause much larger deposits of spray than they had anticipated.(A) weather conditions that could not be foreseen, and pilot errors often cause much larger deposits of spray than they had(B) weather conditions that cannot be foreseen, and pilot errors often cause much larger deposits of spray than(C) unforeseeable weather conditions, and pilot errors are the cause of much larger deposits of spray than they had(D) weather conditions that are not foreseeable, and pilot errors often cause much larger deposits of spray than(E) unforeseeable weather conditions, and pilot errors often cause much larger deposits of spray than they had
Physics
1 answer:
12345 [234]3 years ago
6 0

Answer:

B) weather conditions that cannot be foreseen, and pilot errors often cause much larger deposits of spray than

Explanation:

Option B obeys the principle of parallelism because the two phrases, " can be carefully planned" and "cannot be foreseen" follow the same grammatical structure. Option A does not obey parallelism because " can be carefully planned" and "could not be foreseen" do not follow the same grammatical structure.

The phrase " they had anticipated" in the other options apart from B do not have a matching subject. Pilot errors is the subject in this sentence and it is not expected to anticipate anything, only the pilots can.

Moreover, "that cannot be foreseen" is more parallel to "can be carefully planned" that "unforeseeable" or "foreseeable" used in the other options

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Diamonds are usually found in pipes 50 to 200 m across made of ________.
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Properties seen when one substance changes to another are know as ____ properties
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Answer: chemical property

Explanation:

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if a 0.040-kg stone is whirled horizontally on the end of a 60-m string at a speed of 4.4 m/s, what is the centripetal force ? *
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Answer:

0.013N

Explanation:

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3 years ago
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A ball is thrown horizontally from the top of a 60.0-m building and lands 100.0 m from the base of thebuilding. Ignore air resis
Bumek [7]

Answer:

a)3.5s

b)28.57m/S

c)34.33m/S

d)44.66m/S

Explanation:

Hello!

we will solve this exercise numeral by numeral

a) to find the time the ball takes in the air we must consider that vertically the ball experiences a movement with constant acceleration whose value is gravity (9.81m / S ^ 2), that the initial vertical velocity is zero, we use the following equation for a body that moves with constant acceleration

Y= VoT+0.5gt^{2}

where

Vo = Initial speed =0

T = time

g=gravity=9.81m/s^2

y = height=60m

solving for time

Y=0.5gt^2\\t=\sqrt{\frac{Y}{0.5g} } \\t=\frac{60}{0.5(9.81)} \\

T=3.5s

b)The horizontal speed remains constant since there is no horizontal acceleration. with the value of the distance traveled (100m) and the time that lasts in the air (3.5s) we estimate the horizontal speed

V=\frac{x}{t} =\frac{100}{3.5}=28.57m/s

c)

to find the final vertical velocity we use the equations for motion with constant velocity as follows

Vf=Vo+g.t    

Vf=0+(9.81 )(3.5)=34.335m/S          

d)Finally, to find the resulting velocity, we add the horizontal and vertical velocities vectorially, this is achieved by finding the square root of the sum of its squares

V=\sqrt{Vx^2+Vy^2} =\sqrt{34.33^2+28.57^2} =44.67m/S

7 0
3 years ago
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