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stellarik [79]
3 years ago
7

ANSWER ASAP 1. Which mixture can be classified as a homogeneous mixture?

Chemistry
1 answer:
aleksklad [387]3 years ago
8 0

1. Tap water is a homogenous mixture as the minerals in it are equally distributed.

2. The substance that make up the compound can be determined using a chemical formula.

3. You can use filtration. After you dissolved the salt in the mixture in water, you can filter out the sand.



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7. Given a 32.0 g sample of methane gas (CH), determine the pressure that would be exerted on a container with
pishuonlain [190]

Answer:

P = 58.52 atm

Explanation:

Given data:

Mass of sample = 32.0 g

Pressure of sample = ?

Volume of gas = 850 cm³

Temperature of gas = 30°C

Solution:

Number of moles of gas:

Number of moles = mass/molar mass

Number of moles = 32.0 g/ 16 g/mol

Number of moles = 2 mol

Pressure of gas:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

30+273 = 303 K

850 cm³ × 1L /1000 cm³ = 0.85 L

by putting values,

P× 0.85 L = 2 mol × 0.0821 atm.L/ mol.K  × 303 K

P = 49.75 atm.L/ 0.85 L

P = 58.52 atm

5 0
3 years ago
Hello wonderful people and Good morning, or afternoon
PtichkaEL [24]
He sounds so cute!!!!!
6 0
3 years ago
What is the value of δg°' (or, to put it another way, the cost) when 2nadp+ and 2h2o are converted to 2nadph plus 2h+ plus o2?
svp [43]
The answer is 104.9, i dont know how though
4 0
4 years ago
Read 2 more answers
qual a concentração de uma solução contendo 50g de cloreto de sódio dissolvidos em 250ml de solução​
anygoal [31]

Answer:

200 g/L

Explanation:

The concentration of a solution (also called molarity) can be calculated with the formula:

M=\frac{m}{V}

where

m is the mass of the solute

V is the volume of the solution

For the solution in this problem we have:

m = 50g is the mass of the solute

V = 250 mL = 0.250 L is the volume of the solution

Therefore, the concentration of the solution is:

M=\frac{50 g}{0.250 L}=200 g/L

6 0
3 years ago
A client with diabetes carries insulin with him at all times. At 11:35, he obtains a blood glucose reading of 218 mg/dL (12.1 mm
Soloha48 [4]

Answer:

The correct answer is "Short acting".

Explanation:

The client gets a blood glucose reading of 218 mg/dL (12.1 mmol/L), and immediately supplies a dose of short-acting insulin. Normal blood glucose levels are between 70 and 100 mg/dl fasting and less than 140 mg/dl two hours after each meal. In this way, the type of insulin that should be injected is short-acting, since your blood glucose level is much higher than the limit set for before eating.

Have a nice day!

4 0
3 years ago
Read 2 more answers
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