Answer:
No
Explanation:
The vertical component of Jack's initial velocity is:
5.0
⋅
sin
30
∘
=
5.0
⋅
1
2
=
2.5
m/s
With gravitational acceleration
9.8
m/s
2
, he will reach the highest point of his trajectory after:
2.5
9.8
≈
0.255
s
The average vertical component of his velocity in that
0.255
s
will be:
1
2
⋅
2.5
=
1.25
m/s
So the highest point of his trajectory will be:
0.255
⋅
1.25
≈
0.32
m
So he will pass approximately
7
cm
above the top of the candle.
The horizontal component of his velocity will be a constant:
5.0
⋅
cos
30
∘
=
5.0
⋅
√
3
2
≈
4.33
m/s
So Jack's trajectory will be substantially longer than it is high and he will spend little time anywhere near above the candle.
Answer:
241,274.32 inches
Explanation:
How far will he travel if the rear wheel makes 1200 revolutions on the road?
Since the rear wheel makes one revolution in the distance of a circumference of a circle, C with diameter, d = 16 inches
C = πd²/4
So, the distance, travelled in 1200 revolutions is D = 1200 × C = 1200πd²/4
Substituting d = 16 into D, we have
D = 1200πd²/4
D = 1200π(16)²/4
D = 76800π
D = 241,274.32 inches
Answer:
The answer is below
Explanation:
a) Given that the modulus of elasticity (E) = 317 GPa, to find the modulus of elasticity (in GPa) for the nonporous material (
), we use the formula:
b) If the porosity P = 11.1%, then the modulus of elasticity is:
We have the relation
where 
denotes the velocity of a body A relative to another body B; here I use B for boat, E for Earth, and R for river.
We're given speeds
Let's assume the river flows South-to-North, so that
and let 
be the angle made by the boat relative to East (i.e. -90° corresponds to due South, 0° to due East, and +90° to due North), so that
Then the velocity of the boat relative to the Earth is
The crossing is 153.0 m wide, so that for some time 
we have
which is minimized when 
so the crossing takes the minimum 30.0 s when the boat is pointing due East.
It follows that
The boat's position 
at time is
so that after 30.0 s, the boat's final position on the other side of the river is
and the boat would have traveled a total distance of
ANOTHER RUNNING DOG
Explanation:
In the given question it is to find a suitable reference point to describe the motion of dog. Here I could suggest that it is better to compare the dog with another running dog to create the relative speed difference to get a reliable motion variation.
Because the motion of dog is in the linear with respect to the another dog and to the acceleration produced by the dog in the required interval is easy to calculate with respect to another dog which is already in motion.
Hence, I suggest that Motion of dog can be analysed better by analyse the motion variation of dog with another dog running.
