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777dan777 [17]
3 years ago
10

What is the frequency of a sound wave directly related to?

Physics
1 answer:
Mama L [17]3 years ago
8 0
The frequency of a sound wave is the number of cycles of a sound wave per second or Hertz (Hz). The frequency can be calculated by dividing wavelength by time (Figure 1.3). A small wavelength will yield a higher frequency, whereas a larger wavelength will yield a smaller frequency.
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Electricity that comes into our homes from the grid is known as:
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Power grid
All the poles and wires you see along the highway and in front of your house are called the electrical transmission and distribution system. Today, generating stations all across the country are connected to each other through the electrical system (sometimes called the "power grid").
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2 years ago
A projectile is fired vertically from Earth's surface with an initial speed v0. Neglecting air drag, how far above the surface o
lidiya [134]
This may helpv^2=u^2+2as. v=0 at top of flight. a=acceleration of gravity(vo^2)/2a=s.
3 0
3 years ago
Jorge visits Panama city, Florida during the month of may. he feels a shore breeze blowing from the ocean on the beach. what cau
Wittaler [7]
The answer is a.) the ocean is colder than the land.
Thus, Jorge visits Panama city, Florida during the month of may. he feels a shore breeze blowing from the ocean on the beach because Jorge visits Panama city, Florida during the month of may. he feels a shore breeze blowing from the ocean on the beach.

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3 0
3 years ago
Your 64-cm-diameter car tire is rotating at 3.3 rev/swhen suddenly you press down hard on the accelerator. After traveling 250 m
umka21 [38]

Answer:

0.76 rad/s^2

Explanation:

First, we convert the original and final velocity from rev/s to rad/s:

v_o = 3.3\frac{rev}{s} * \frac{2\pi rad}{1rev} =20.73 rad/s

v_f = 6.4\frac{rev}{s} * \frac{2\pi rad}{1rev}=40.21 rad/s

Now, we need to find the number of rads that the tire rotates in the 250m path. We use the arc length formula:

D = x*r \\x = \frac{D}{r} = \frac{250m}{0.64m/2} = 781.25 rads

Now, we just use the formula:

w_f^2-w_o^2=2\alpha*x

\alpha =\frac{w_f^2-w_o^2}{2x} = \frac{(40.21rad/s)^2-(20.73rad/s)^2}{2*781.25rad} = 0.76 rad/s^2

6 0
3 years ago
Read 2 more answers
Which statement best describes the relationship between an object's density and its index of refraction? as the optical density
babunello [35]
For future references, the answer is B.
4 0
3 years ago
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