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3 years ago

NEED THIS ANSWER ASAP!

Physics

2 answers:

Akimi4 [234]3 years ago

5 0

Answer:

4.36 × 10⁶ litres

Explanation:

Power = workdone/time

1926×10⁶ = (m×9.81×45)/1

m = 4.362895005 × 10⁶ kg

Volume = 4.362895005 × 10⁶ litres

Sveta_85 [38]3 years ago

4 0

h = average height of Niagara falls = 45 m

P = power generated by Stations I and II together = 1926 MW = 1926 x 10⁶ Watt

m = mass of water required to go over the falls

g = acceleration due to gravity

t = time = 1 sec

Power generated is given as

Power generated = potential energy lost/time

P = mgh/t

1926 x 10⁶ = m (9.8) (45)/1

m = 1926 x 10⁶ /(9.8 x 45)

m = 4.4 x 10⁶ kg

it is given that , 1 kg = 1 litre

hence

hence Volume of water = V = 4.4 x 10⁶ litre

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What will happen when a light bulb is removed from the circuit below, leaving a gap?

Charra [1.4K]

Answer:

The remaining light bulbs will go out.

Explanation:

The light bulb that was taken out routed power to the other light bulbs, there for, not giving power to the next light bulbs will make them turn off or, "go out". This may be incorrect, as you did not provide a picture of the circuit.

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3 years ago

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An electric Kettle is rated at 25 W. Calculate the quantity of heat generated in 2s

MatroZZZ [7]

Answer:

Energy consumed by the electric kettle in 9.5 min =Pt=(2.5×10

)×(9.5×60)=14.25×10

Energy usefully consumed =msΔT=3×(4.2×10

)×(100−15)=10.71×10

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3 years ago

Question 3 of 10

Mazyrski [523]

Answer:

B . energy cannot be created or destroyed

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2 years ago

The electromagnetic wave that delivers a cellular phone callto

spin [16.1K]

Answer:

$E=2.41\cdot 10^{-5} J$

Explanation:

The intensity of an electromagnetic wave can be expressed in terms of the magnetic field using the next relationship:

$I_{average}=\frac{cB_{0}^{2}}{2\mu_{0}}$ (1)

c is the speed of light (3*10⁸ m/s)
μ₀ is the permeability of free space (in vacuum ) (1.26*10⁻⁶ N/A²)
B₀ is the magnetic field

$I_{average}=\frac{3\cdot 10^{8}(1.5\cdot 10^{-10})^{2}}{2\cdot 1.26\cdot 10^{-6}}$

$I_{average}=2.68\cdot 10^{-6} W/m^{2}$

Now, let's define the relationship between power (P) and average intensity (I).

$I_{average}=\frac{P}{A}$

P is the power
A is the area crossed

So we can calculate the power.

$P=I_{average}\cdot A=2.68\cdot 10^{-6}\cdot 0.20=5.37\cdot 10^{-7} W$

Finally, energy is the product of P times time, so:

$E=P\cdot t=5.37\cdot 10^{-7} \cdot 45=2.41\cdot 10^{-5} J$

I hope it helps you!

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2 years ago

If spring has a spring constant of 500 N/m and is stretched .50 meters,how much energy is stored in the spring ((show work for f

Free_Kalibri [48]

Answer:

The energy stored is: 62.5 Joules

Explanation:

Given

$k = 500N/m$ --- spring constant

$x = 0.5m$ --- stretch

Required

The amount of energy

This is calculated as:

$U = \frac{1}{2} kx^2$

$U = \frac{1}{2} * 500N/m * (0.5m)^2$

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$U = 62.5\ J$

7 0

2 years ago