Answer:
further tightening is required.
Explanation:
The beat created / sec = difference of frequencies
Initial beat heard = 2
so difference of frequencies = 2
after tightening beat heard = 1
difference of frequencies decreases because frequency of tuning fork was higher than piano sound.
on further tightening difference decreases because tightening increases the frequency of piano hence further tightening is required for resonance.
4.65 × 10⁴ Joules of heat is released upon converting one mole of steam to water.

<h3>Further explanation</h3>
Specific Heat Capacity is the amount of energy needed to raise temperature of 1 kg body for 1°C.

<em>Q = Energy ( Joule )</em>
<em>m = Mass ( kg ) </em>
<em>c = Specific Heat Capacity ( J / kg°C ) </em>
<em>Δt = Change In Temperature ( °C )</em>
Let us now tackle the problem!

<u>Given:</u>
initial temperature of steam = t = 100.0°C
specific heat capacity of water = c = 4.186 J/gK
mass of steam = m = 18.0 gram
final temperature of water = t' = 25.0°C
specific latent heat of vaporization of water = Lv = 2268 J/g
<u>Asked:</u>
heat released = Q = ?
<u>Solution:</u>
![\boxed {\large {\texttt{steam 100}^oC \overset{[Q_1]}{\rightarrow} \texttt{water 100}^oC \overset{[Q_2]}{\rightarrow} \texttt{water 25}^oC}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Clarge%20%7B%5Ctexttt%7Bsteam%20100%7D%5EoC%20%5Coverset%7B%5BQ_1%5D%7D%7B%5Crightarrow%7D%20%5Ctexttt%7Bwater%20100%7D%5EoC%20%5Coverset%7B%5BQ_2%5D%7D%7B%5Crightarrow%7D%20%5Ctexttt%7Bwater%2025%7D%5EoC%7D%7D)







<h3>Learn more</h3>

<h3>Answer details </h3>
Grade: College
Subject: Physics
Chapter: Thermal Physics

Keywords: Heat , Temperature , Block , Aluminium , Ice , Cold , Water
Answer:
2/B
6/E
7/F
12/6
Explanation:
Hope this helps i dont know ither i will put if i think of them
Answer:
D. momentum
Explanation:
Momentum is the product of velocity and mass which is the two variables the paragraph talked about.
Answer:
a) 1273.23 A/m^2
b) 7.19*10^-5 m/s
c) 236881.7 Ohms
Explanation:
(a) To find the current density you use the following formula:

I: current in the wire
A: cross area of the wire
r: radius of the wire

(b) The electron drift speed is given by:

n: number of conduction electrons per m^3
q: charge of the electron = 1.6*10^-19C
The number of free electrons is calculated by using:

Next, you replace the values of the parameters in the equation for vd:

(c) The conductivity is given by:

You first calculate R:

Next, replace for sigma:
