Answer:
3. It is a passive process in which molecules move from a region of higher concentration to a region of lower concentration.
Explanation:
<em>Diffusion can be defined as the movement of solute or gaseous molecules from the region in which they have higher concentration to the regions in which they have lower concentration until they become evenly distributed across the two regions. </em>
<em>Diffusion is a passive process, that is, it requires no energy.</em>
Option 3 is the correct option.
I believe the correct answer is kinetic energy.
We know that kinetic energy is the movement of any object, no matter its size.
Mechanical energy is a type of kinetic energy, which involves the movement of larger objects.
I hope I helped!
If you need a more thorough explanation, don't hesitate to message me or leave a comment down below.
Here's a video that explains energy:
https://www.khanacademy.org/science/physics/work-and-energy/work-and-energy-tutorial/v/work-and-energy-part-2?modal=1
Answer:
Explanation:
The options is not well presented
This are the options
A. θ = at³ + b
B. θ = at² + bt + c
C. θ = at² — b
D. θ = Sin(at)
So, we want to prove which of the following option have a constant angular acceleration I.e. does not depend on time
Now,
Angular acceleration can be determine using.
α = d²θ / dt²
α = θ''(t)
So, second deferential of each θ(t) will give the angular acceleration
A. θ = at³ + b
dθ/dt = 3at² + 0 = 3at²
d²θ/dt² = 6at
α = d²θ/dt² = 6at
The angular acceleration here still depend on time
B. θ = at² + bt + c
dθ/dt = 2at + b + 0 = 2at + b
d²θ/dt² = 2a + 0 = 2a
α = d²θ/dt² = 2a
Then, the angular acceleration here is constant is "a" is a constant and the angular acceleration is independent on time.
C. θ = at² —b
dθ/dt = 2at — 0 = 2at
d²θ/dt² = 2a
α = d²θ/dt² = 2a
Same as above in B. The angular acceleration here is constant is "a" is a constant and the angular acceleration is independent on time.
D. θ = Sin(at)
dθ/dt = aCos(at)
d²θ/dt² = —a²Sin(at) = —a²θ
α = d²θ/dt² = -a²θ
Since θ is not a constant, then, the angular acceleration is dependent on time and angular displacement
So,
The answer is B and C
Answer:
ΔT / Δx = 771 K/m
ΔT = 771 x 0.0475 = 36.62 k
Explanation:
P = 31700 W, A = 0.819 m^2, Δx = 0.0475 m, K = 50.2 W /m k
Use the formula of conduction of heat
H / t = K A x ΔT / Δx
So, ΔT / Δx = P / K A
ΔT / Δx = 31700 / (50.2 x 0.819)
ΔT / Δx = 771 K/m
Now
ΔT = 771 x 0.0475 = 36.62 k