Answer:
λ = 1.4 × 10^(-7) m
Explanation:
We are given;
distance of eye piece from the source;D = 1.5 m
distance between the virtual sources;d = 7.5 × 10^(-4) m
To find the wavelength, we will use the formula for fringe width;
X = λD/d
Where X is fringe width, λ is wavelength, while d and D remain as before.
Now, fringe width = eye-piece distance moved transversely/number of fringes
Eye piece distance moved transversely = 1.88 cm = 1.88 × 10^(-2) m
Thus,
Fringe width = (1.88 × 10^(-2))/10 = 1.88 × 10^(-3) m
Thus;
1.88 × 10^(-3) = λ(1.5)/(7.5 × 10^(-4))
λ = [1.88 × 10^(-3) × (7.5 × 10^(-4))]/1.5
λ = 1.4 × 10^(-7) m
Answer:a plate is a rigid segment Of The earth's lithosphere that moves horizontally and adjoins other plates along then zone of seismic activity.
Explanation:
A plate is a rigid segment Of The earth's lithosphere that moves horizontally and adjoins other plates along then zone of seismic activity.plates may include portion of both continents and ocean basin.
Answer:
32 turns
Explanation:
From the expression for the induced emf,
E = (N)(B)(A) w
E = emf = 24 V
N = number of turns = ?
B = magnetic field strength = 0.10 T
A = Cross sectional Area of the loop = 100 cm² = 0.01 m²
w = Angular speed = (2πf) = (2π × 120) = 754.3 rad/s
24 = N (0.1)(0.01)(754.3)
N = (24/0.7543)
N = 31.8 ≈ 32 turns.
Hope this Helps!!!
The correct answer would be B.) 98°c-102°c
Answer:
Sound wave is a longitudinal wave that propagates in a medium
Explanation:
<em>Part A:</em> (C) Sound wave is propagation of pressure fluctuations in a medium.
<em>Part B: </em>(C) Pressure fluctuations travel along the direction of propagation of the sound wave.
<em>Part C: </em>(A) Yes air play a role in the propagation of the human voice from one end of the lecture hall to the other.
