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Rom4ik [11]
4 years ago
12

Which force keeps an object moving in a circle

Physics
2 answers:
AlekseyPX4 years ago
8 0

Answer:

Centripetal force

Explanation:

An object moving in a circle experiences a centripetal acceleration.  The force that causes this acceleration is called centripetal force.

NeX [460]4 years ago
7 0

Answer:

The force is called Centripetal Force

Explanation:

Force simply means a push or pull on an object which causes it to move from it's original position.

We have different types of force, one of which is the Centripetal Force

The Centripetal Force is a force that makes a body to move in an circular position. Example of Centripetal Force is turning a car.

Centripetal Force is normally calculated with the formula

Fc =  mv²/r

Where:

Fc = centripetal force

m = mass

v = velocity

r = radius

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You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body
stellarik [79]

A) The change in internal chemical energy is 1.15\cdot 10^7 J

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

P=Fv

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

P=(80)(8.0)=640 W

The energy output is related to the power by the equation

P=\frac{E}{t}

where:

P = 640 W is the power output

E is the energy output

t = 30 min \cdot 60 = 1800 s is the time elapsed

Solving for E,

E=Pt=(640)(1800)=1.15\cdot 10^6 J

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J

B)

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

E=1.15\cdot 10^7 J

Here we want to find the time t' needed to convert an amount of chemical energy of

E'=3.8\cdot 10^5 J

So we can setup the following proportion:

\frac{t}{E}=\frac{t'}{E'}

And solving for t',

t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min

Learn more about power and energy:

brainly.com/question/7956557

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