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lions [1.4K]
3 years ago
15

A normal human heart, beating about once per second, creates a maximum 4.00 mV potential across 0.400 m of a person's chest, pro

ducing a 1.00 Hz electromagnetic wave. What is the maximum electric field strength produced
Physics
2 answers:
Ipatiy [6.2K]3 years ago
4 0

Answer:

Explanation:

Given:

Maximum potential, Vmax = 4 mV

= 0.004 V

Distance, d = 0.4 m

Electric field, E = potential difference, V/distance, d

Emax = 0.004/0.4

= 0.01 V/m

kvasek [131]3 years ago
3 0

Answer:

The maximum electric field strength = 0.01 V/m

Explanation:

Given

ΔV(max) = 4.00 mV = 0.004 V

d = 0.400 m

f = 1.00 Hz

Maximum electric field = (maximum potential)/(length)

Maximum electric field = E(max)

Maximum potential = 4.00 mV = 0.004 V

Length = 0.400 m

E(max) = (0.004/0.4) = 0.01 V/m

Hope this Helps!!!

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A mass m is tied to an ideal spring with force constant k and rests on a frictionless surface. The mass moves along the x axis.
7nadin3 [17]

Answer:x=\frac{x_m}{\sqrt{2}}

Explanation:

Given

initially mass is stretched to x_m

Let k be the spring Constant of spring

Therefore Total Mechanical Energy is \frac{kx_m^2}{2}

Position at which kinetic Energy is equal to Elastic Potential Energy

K=\frac{mv^2}{2}

U=\frac{kx^2}{2}

it is given

k=U

thus 2U=\frac{kx_m^2}{2}

2\times \frac{kx^2}{2}=\frac{kx_m^2}{2}

2x^2=x_m^2

x=\frac{x_m}{\sqrt{2}}

3 0
4 years ago
If you pull a wool sweater over your head, you will often end up with a wild hairdo. Your hair is hard to comb and wants to stan
Sergio [31]
Becasue when you rubbed your hair while you were putting on your sweater it caused it to rub against together causing electricity thingy lol. and thats why your hair goes straigh tup.
5 0
3 years ago
A clown at a birthday party has brought along a helium cylinder, with which he intends to fill balloons. When full, each balloon
Furkat [3]

Answer:

11

Explanation:

According to Boyle's law:

P\times V=constant

Thus,

P_{cylinder}\times V_{cylinder}=n\times P_{balloon}\times V_{balloon}

Where, n is the number of the balloons

From the question, it is given that:

For balloon:

P = 1.2\times 10^5 Pa

V = 0.040 m³

For cylinder:

P = 1.80\times 10^7 Pa

V = 0.0031 m³

So,

1.80\times 10^7\times 0.0031=n\times 1.2\times 10^5\times 0.040

n = 11.625

<u>So, Maximum number of balloons = 11</u>

7 0
3 years ago
How do an object's mass<br> and velocity relate to its<br> momentum?
uysha [10]
Momentum depends upon the variables mass and velocity. In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object.
7 0
3 years ago
A boy kicks a football from ground level. The ball takes 3 seconds to reach its maximum height. What is the angle of the initial
ruslelena [56]
<h2>The angle of the initial velocity with respect to the horizontal is 85.14°</h2>

Explanation:

Given that the ball takes 3 seconds to reach its maximum height.

Consider the vertical motion of ball till maximum height.

We have equation of motion v = u + at

     Acceleration, a = -9.81 m/s²

     Final velocity, v = 0 m/s    

     Time, t = 3 s

     Substituting

                      v = u + at  

                      0 = u + -9.81 x 3

                      u = 29.43 m/s

Initial vertical velocity is 29.43 m/s.

Now consider horizontal motion of ball.

Time of flight of ball = 2 x Time to reach maximum height = 2 x 3 = 6 s

Displacement = 15 m

We have equation of motion s = ut + 0.5 at²

        Displacement, s = 15 m

        Acceleration, a = 0 m/s²  

        Time, t = 6 s      

     Substituting

                      s = ut + 0.5 at²

                      15 = u x 6 + 0.5 x 0 x 6²

                      u = 2.5 m/s

Initial horizontal velocity is 2.5 m/s

Let r be the initial velocity and θ be the angle with horizontal

              Initial vertical velocity = rsinθ = 29.43 m/s

              Initial horizontal velocity = rcosθ = 2.5 m/s

Dividing

              \frac{rsin\theta }{rcos\theta }=\frac{29.43}{2.5}\\\\tan\theta=11.77\\\\\theta=85.14^0

The angle of the initial velocity with respect to the horizontal is 85.14°

4 0
3 years ago
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