Question

Calculate the magnetic field strength needed on a 170-turn square loop 22 cm on a side to create a maximum torque of 295 N·m if the loop is carrying 20 A.

Answer 1

Answer:

B = 1.823 T.

Explanation:

Given,

Number of turns,N = 170 turn

Side of square loop,L = 22 cm

Maximum torque, τ = 295 N.m

Current on the loop, I = 20 A

Magnetic strength =  ?

Torque = N BIA

300 = 170 x  B x 20 x  0.22²

300 = 164.56 B

B = 1.823 T.

Hence, the magnetic field strength is equal to B = 1.823 T.