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3 years ago

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Calculate the magnetic field strength needed on a 170-turn square loop 22 cm on a side to create a maximum torque of 295 N·

m if the loop is carrying 20 A.

1 answer:

Triss [41]3 years ago

7 0

Answer:

B = 1.823 T.

Explanation:

Given,

Number of turns,N = 170 turn

Side of square loop,L = 22 cm

Maximum torque, τ = 295 N.m

Current on the loop, I = 20 A

Magnetic strength = ?

Torque = N BIA

300 = 170 x B x 20 x 0.22²

300 = 164.56 B

B = 1.823 T.

Hence, the magnetic field strength is equal to B = 1.823 T.

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