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Brilliant_brown [7]
3 years ago
10

Which of these describes Busan?

Chemistry
2 answers:
Ilya [14]3 years ago
5 0

The answer for this question is B.

iren [92.7K]3 years ago
4 0

The correct answer is C. The largest port city in South Korea located on the southern tip of the Korean Peninsula

Explanation:

Busan is an important city in South Korea, which is an Asiatic country located in the east of the continent. This city is the most important in the country after Seoul, which is the capital city. Moreover, this city is relevant because it acts as one of the most important ports in South Korea, which makes this city an important trade center. Besides this, in terms of geographical location, Busan is located in the south of the Korean Peninsula that includes both South Korea and North Korea. Thus, the statement that describes Busan is "The largest port city in South Korea located on the southern tip of the Korean Peninsula".

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A. Ability to burn

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In a 1.0-liter container there are, at equilibrium, 0.10 mole h2, 0.20 mole n2, and 0.40 mole nh3. what is the value of kc for t
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The reaction involved here would be written as:

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Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh
Dima020 [189]

<u>Answer:</u> The \Delta G^o for the given reaction is -7.84\times 10^4J

<u>Explanation:</u>

For the given chemical reaction:

2ClO_2^-(aq.)+Cl_2(g)\rightarrow 2ClO_2(g)+2Cl^-(aq.)

Half reactions for the given cell follows:

<u>Oxidation half reaction:</u> ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V  ( × 2)

<u>Reduction half reaction:</u> Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=1.36-(0.954)=0.406V

To calculate standard Gibbs free energy, we use the equation:

\Delta G^o=-nFE^o_{cell}

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

E^o_{cell} = standard cell potential = 0.406 V

Putting values in above equation, we get:

\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J

Hence, the \Delta G^o for the given reaction is -7.84\times 10^4J

4 0
3 years ago
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