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Tanzania [10]
3 years ago
6

A positive charge distribution exists within a nonconducting spherical region of radius a. The volume charge density ρ is not un

iform but varies with the distance r from the center of the spherical charge distribution, according to the relationship ρ=βr for 0<=0<=a, where β is a positive constant, and ρ=0, and r>a.A. Show that the total charge Q in the spherical region of radius a is βπa^4B. In terms of β,r,a and fundamential constants, determine the magnitude of the electric field at a point a from distance r from the center of the spherical charge distribution for each of the following cases.i. r>aii. r=aiii 0
Physics
1 answer:
baherus [9]3 years ago
5 0

A negative charge and a positive charge

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If a body having mass 40kg started moving initially with rest and it takes a velocity of 20m/sec in time 4 seconds. Find the val
baherus [9]

{\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\

\:\:\:\:\bullet\:\:\:\sf{Mass \ of \ the \ body \ (m) = 40 \ kg}

\:\:\:\:\bullet\:\:\:\sf{Final \ velocity \ of \ the \  body \ (v) = 20 \ m/s}

\:\:\:\:\bullet\:\:\:\sf{Initial \ velocity \ of \ the \  body \ (u) = 0}

\\

{\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\

\:\:\:\:\bullet\:\:\:\sf{Force \ exerted \ by \ the \  body \ ( F)}

\\

{\mathfrak{\underline{\purple{\:\:\: Solution:-\:\:\:}}}} \\ \\

☯ <u>Using 1st equation of motion </u>

\\

\dashrightarrow\:\: \sf{v = u + at}

\\

\dashrightarrow\:\: \sf{20 = 0 + a(4)}

\\

\dashrightarrow\:\: \sf{20 = 4a}

\\

\dashrightarrow\:\: \sf{\dfrac{\cancel{20}}{\cancel{4}} = a}

\\

\dashrightarrow\:\: \sf{a = 5}

\\

☯ <u>Now, Finding the force exerted </u>

\\

\dashrightarrow\:\: \sf{F = ma}

\\

\dashrightarrow\:\: \sf{F = 40 \times 5}

\\

\dashrightarrow\:\: \sf{F = 200 \ N}

\\

☯ <u>Hence</u>, \\

\:\:\:\:\star\:\:\:\sf{The \ force \ exerted \ by \ the \ body \ is \ 200N}

8 0
3 years ago
a hot iron bar is placed 100ml 22C water. the water temperature rises to 32C. how much heat did the water gain and how much heat
Sergeu [11.5K]

Answer:

  • Water gained: 10
  • Iron lost: -10

Explanation:

Given: Hot iron bar is placed 100ml 22C water, the water temperature rises to 32C

To find: How much heat the water gain, how much heat did the iron bar lost

Formula:Q = change T x C x M

Solve:

<u>How much heat water gained</u>

Initial heat = 22, then rose to 32. To find how much heat the water gained, simply subtract the current heat by the initial heat.

                                              32 - 22 = 10

The water gained 10 amounts of heat.

<u>How much heat Iron lost</u>

Current heat = 32, then dropped to 22. To find how much heat the Iron lost, simply subtract the initial heat by the current heat.

                                                   22 - 32 = -10

The Iron lost -10 amounts of water.      

4 0
3 years ago
What would happen if the pilot did not keep the airplane "trimmed"
Mademuasel [1]

Answer:

In explanation

Explanation:

Pilots who dont use trim often like the feeling of holding constant back pressure because The heavier control forces makes it more difficult to over-control the airplane inside the turn, so it gives the sense of a more stable flight

3 0
3 years ago
The first electric generators used direct current, so they needed to be reversed manually on a regular basis in order to work pr
djyliett [7]
Could I see the questions
4 0
3 years ago
A subway train accelerates from rest at one station at a rate of 1.30 m/s^2 for half of the distance to the next station, then d
Minchanka [31]

This problems a perfect application for this acceleration formula:

         Distance = (1/2) (acceleration) (time)² .

During the speeding-up half:     1,600 meters = (1/2) (1.3 m/s²) T²
During the slowing-down half:    1,600 meters = (1/2) (1.3 m/s²) T²

Pick either half, and divide each side by  0.65 m/s²: 

                         T² = (1600 m) / (0.65 m/s²)

                         T = square root of (1600 / 0.65) seconds

Time for the total trip between the stations is double that time.

                         T =  2 √(1600/0.65) = <em>99.2 seconds</em>  (rounded)


7 0
3 years ago
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