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Brums [2.3K]
4 years ago
13

During which of the following activities may in inflatable personal flotation device to be used

Physics
1 answer:
Alla [95]4 years ago
5 0
They may be used whenever you are not experienced with swimming and you are near the water such as swimming, canoeing, etc
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A model airplane with mass 0.5 kg hangs from a rubber band with spring constant 45 N/m. How much is the rubber band stretched wh
e-lub [12.9K]
Multiply 0.5 by 9.8 then divide it by 45. 0.11m
8 0
3 years ago
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A plumber heats a plastic pipe, softens it, shapes it, and then lets it cool. After it is hardened, the
aev [14]

Answer:

thermoset

Explanation:

A thermoset material is a polymer that is irreversibly hardened by curing. Curing is induced by heat and cannot be undone because the polymers cross link during the process, creating permanent chemical bonds.

3 0
3 years ago
If it takes 100 N to move a box 5 meters, what is the work done on the box?
jeyben [28]

Answer:  D.   500 J

=========================================================

Explanation:

To find the amount of work done, we multiply the force by displacement

work = force*displacement

work = (100 N)*(5 m)

work = (100*5) Nm

work = 500 J

In this case, "Nm" refers to "Newton meters" and not "nanometers"

1 newton meter is equal to 1 joule

7 0
3 years ago
A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used
Blizzard [7]

Answer:

a,b)   #_ {electron} = 1.64 10¹⁹ electrons, c)  R = 19.54  Ω, d)   V = 10.3 V

Explanation:

a and b) The current is defined as the number of electrons that pass per unit of time

let's look for the load

            Q = I t

            Q = 0.526  5

            Q = 2.63 C

Let's use a direct rule of three proportions. If an electron has a charge of 1.6 10⁻¹⁹ C, how many electrons does 2.63 C have?

           #_ {electron} = 2.63 C (1 electron / 1.6 10⁻¹⁹)

           #_ {electron} = 1.64 10¹⁹ electrons

         

c) the resistance of a wire is given by

          R = ρ l / A

           

where the resistivity of tungsten is 5.6 10⁻⁸ Ω

the area of ​​the wire is

           A = π r2 = π d²/4

         

we substitute

            R = \rho \ l \ \frac{4}{\pi  d^2}

let's calculate

           R = 5.6 10⁻⁸  0.580 \frac{4}{ \pi  (0.046 \ 10^{-3})^2 }

           R = 19.54  Ω

d) let's use ohm's law

           V = i R

            V = 0.526 19.54

            V = 10.3 V

7 0
3 years ago
What is the phenomenon that can occur if the percentage of oxygen is higher in the air?
timama [110]

Answer:

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6 0
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