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snow_lady [41]
3 years ago
8

Which term describes weathering?

Chemistry
2 answers:
erastova [34]3 years ago
7 0

Answer:

Breaks down rocks.

Explanation:

Weathering is the breaking down of rocks often with water. For example a sea shell will get batered with water and over time form sand.

Nastasia [14]3 years ago
4 0

Answer:

Weathering means the materials like rocks, soil, woods, etc they break down in due course of time due to certain atmospheric conditions and many other biological factors.

are -

- creates sediment

- breaks down rock

- carries away fragments

Explanation:

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A chemical reaction with an initial quantity of 1.35 moles of gas is performed in a 4.50-L flask at 24.7°C and under 1.07 atm of
nexus9112 [7]

Answer:

0.488 mol

Explanation:

By the ideal gas law:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.082 atm.L/mol.K), and T is the temperature in K. Thus, after the reaction:

P = 2.92 atm

V = 4.50 L

T = 55.2°C + 273 = 328.2 K

PV = nRT

n = PV/RT

n = (2.92*4.50)/(0.082*328.2)

n = 0.488 mol

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3 years ago
Which of the following would be the least reliable source of information?
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Weekly news magazine
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3 years ago
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How many grams of oxygen are required to react with 12.0 grams of octane(C8H18) in the combustion of octane in gasoline?
solniwko [45]

Answer : 42 grams of oxygen are required.

Explanation :

Step 1 : Write balanced chemical equation.

The combustion reaction of octane with oxygen can be written as,

2 C_{8}H{18} (g)  + 25  O_{2} (g) \rightarrow 16 CO_{2} (g) +18  H_{2}O (g)

Step 2 : Find moles of octane.

The given mass of octane is 12 g

Molar mass of octane is 114.2 g/mol

The moles of octane are calculated as,

moles =\frac{grams}{MolarMass}  =\frac{12g}{114.2g/mol}  = 0.105 mol

We have 0.105 mol octane.

Step 3: Use mole ratio from balanced equation to find moles of O₂

The mole ratio of octane and O₂ is 2 : 25. Let us use this as a conversion factor.

0.105 mol C_{8}H_{18} \times\frac{25mol O_{2}}{2molC_{8}H_{18}}  = 1.31 mol

We have 1.31 mol O₂.

Step 4 : Convert moles of O₂ to grams.

The molar mass of O₂ is 32 g/mol.

The grams of O₂ can be calculated as,

1.31 mol O_{2} \times\frac{32g}{mol}  = 42 grams

42 grams of oxygen are required.

8 0
3 years ago
Nitrogen dioxide reacts with carbon monoxide to produce nitrogen monoxide and carbon dioxide. NO2(g) + CO(g) ⟶ NO(g) + CO2(g) A
Naya [18.7K]

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k[NO_3][CO]

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

NO_2(g)+CO(g)\rightarrow NO(g)+CO_2(g)

The intermediate reaction of the mechanism follows:

Step 1:  2NO_2(g)\rightleftharpoons NO_3(g)+NO(g);\text{ (fast)}

Step 2:  NO_3(g)+CO(g)\rightarrow NO_2(g)+CO_2(g);\text{(slow)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[NO_3][CO]

Hence, the rate law for the reaction is written above.

5 0
4 years ago
Have some points chemistry gang RISE UP
densk [106]

Answer:

I WILL ACHIEVE GREATNESS

Explanation:

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