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Helga [31]
3 years ago
5

Watch the video to determine which of the following relationships correctly depict the relationship between pressure and volume

for a fixed amount of gas at constant temperature according to Boyle’s law. Check all that apply.
a. PV∝P
b. P∝1V
c. PV∝V
d. V∝P
e. V∝1P
f. P∝V
Chemistry
1 answer:
sergij07 [2.7K]3 years ago
7 0

Answer : P\propto \frac{1}{V} and  V\propto \frac{1}{P}

Explanation:

According to Boyle's law, it states that pressure is directly proportional to the volume of the gas for a fixed amount of gas and at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

Thus the correct relation for pressure and volume for a fixed amount of gas at constant temperature according to Boyle’s law is P\propto \frac{1}{V} and  V\propto \frac{1}{P}

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Explanation:

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Answer:

1.) 0.1 M

2.) 0.2 M

3.) 1 M

4.) Solution #3 is the most concentrated because it has the highest molarity. This solution has the largest solute to solvent ratio. The more solvent there is, the lower the concentration and molarity.

Explanation:

To find the molarity, you need to (1) convert grams NaOH to moles (via molar mass from periodic table) and then (2) calculate the molarity (via the molarity equation). All of the answers should have 1 sig fig to match the given values.

Molar Mass (NaOH): 22.99 g/mol + 16.00 g/mol + 1.008 g/mol

Molar Mass (NaOH): 39.998 g/mol

4 grams NaOH           1 mole
----------------------  x  ------------------  = 0.1 moles NaOH
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1.)

Molarity = moles / volume (L)

Molarity = (0.1 moles) / (1 L)

Molarity = 0.1 M

2.)

Molarity = moles / volume (L)

Molarity = (0.1 moles) / (0.5 L)

Molarity = 0.2 M

3.)

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<h3>Nomenclature of Organic compounds</h3>

From the question, we are to determine the name of the given molecule.

To name the compound, we will follow the IUPAC rules.

Some of IUPAC rules are

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The given compound has 8 carbons and a double bond. The root name of the compound is octane.

By <u>IUPAC rules</u>, the compound is an <u>Octene</u>.

Since the double bond is between carbon-1 and carbon-2. The compound becomes 1-octene.

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The diagram for the compound is attached below.

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