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motikmotik
3 years ago
12

Eli takes a typing test and types all 300 words in 1/10 hour. He takes the test a second time and types the words in 1/12 hour w

as he faster or slower on the second attempt? Explain.
Mathematics
1 answer:
anzhelika [568]3 years ago
4 0

Answer:

The second attempt was faster

Step-by-step explanation:

The first attempt took 6 minutes to finish and the second attempt took 5 minutes to finish. 6 minutes is slower than 5 minutes

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In a school of 500 students, a random sample of 60
erastova [34]

it would be  2 people

5 0
3 years ago
8 - 4y + (-2y) + 5 <br><br><br> What is this answer please tell me
Irina-Kira [14]

Answer:

<em>13 - 6y </em>

Step-by-step explanation:

8 - 4y + (-2y) + 5 = <em>13 - 6y</em>

8 0
3 years ago
Read 2 more answers
Find an equation of a line that is tangent to the graph of f and parallel to the given line. Please see picture
ivanzaharov [21]

Answer:

y = 3x - 2 (smaller y-intercept)

y = 3x + 2 (larger y-intercept)

Step-by-step explanation:

First let's write the generic equation of a line:

y = ax + b

This line needs to be parallel to the line 3x - y + 5 = 0, so it needs to have the same slope of this line.

The line 3x - y + 5 = 0 has a slope of 3, so our line has a = 3:

y = 3x + b

Now we need to find the values of b that make this line tangent to the function f(x) = x^3

Let's first find the derivative of f(x) in relation to x:

df(x)/dx = 3x^2

This derivative is the slope of the tangent line to the function for any value of x. We need a slope of 3, so:

3x^2 = 3

x^2 = 1

x = ±1

Now, to find the y-values, we have:

f(1) = 1^3 = 1

f(-1) = (-1)^3 = -1

So, using the points (1,1) and (-1,-1) in our parallel line, we have:

first line using (1,1) : 1 = 3*1 + b

b = -2

second line using (-1,-1) : -1 = -3*1 + b

b = 2

The value of b is the y-intercept of the line, so the line with smaller y-intercept is y = 3x - 2, and the line with larger y-intercept is y = 3x + 2

8 0
3 years ago
An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
Find the Area of the parallelogram 14cm 1 12cm​
Black_prince [1.1K]

Answer:

1568 cm

Step-by-step explanation:

Base x Height = Area

14 x 112 = 1568

4 0
3 years ago
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