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3 years ago

The solubility of a gas is .55 g/l at 8.0 atm pressure. what will be the solubility of the gas at 5.0 atm partial pressure?

1 answer:

8 0

Henry's law states that:

P1/C1 = P2/C2

Where P = Pressure, and C = Solubility
In this case, P1 = 8.0 atm, C1 = 0.55 g/l, P2 = 5.0 atm, C2 =??

Therefore,
C2 = (P2*C1)/P1 = (5*0.55)/8 = 0.344 g/l

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Integrating the velocity equation, we will see that the position equation is:

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Let the velocity of the particle is:

$$v(t)=\sin (\omega t) * \cos ^2(\omega t)$

To get the position equation we just need to integrate the above equation:

$$f(t)=\int \sin (\omega t) * \cos ^2(\omega t) d t$

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Replacing that in our integral we get:

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Where C is a constant of integration.

Now we remember that $u=\cos (\omega t)$

Then we have:

$$f(t)=\frac{\cos ^3(\omega t)}{3}+C$

To find the value of C, we use the fact that f(0) = 0.

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His journey took him 3 hours 15 minutes.

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If a blender is plugged into a 168 V outlet that supplies 80.8 A of current, what amount of

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Power is the rate at which work is done. ... Great power means a large amount of work or energy developed in a short time. For example, when a powerful car accelerates rapidly, it does a large amount of work and consumes a large amount of fuel in a short time.

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