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ANEK [815]
3 years ago
14

The solubility of a gas is .55 g/l at 8.0 atm pressure. what will be the solubility of the gas at 5.0 atm partial pressure?

Physics
1 answer:
garik1379 [7]3 years ago
8 0
Henry's law states that:

P1/C1 = P2/C2

Where P = Pressure, and C = Solubility
In this case, P1 = 8.0 atm, C1 = 0.55 g/l, P2 = 5.0 atm, C2 =??

Therefore,
C2 = (P2*C1)/P1 = (5*0.55)/8 = 0.344 g/l
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As outlaws escape in their getaway ear, which goes 3/4 c, the police officer fires a bullet from a pursuit ear, which only goes
Mariulka [41]

Answer:

a) Bullet will hit

b) Bullets will not hit

Explanation:

Given:

The velocity of the bullet, u = \frac{1}{3}c in the rest frame of the bullet pursuit car

The velocity of the original frame of reference, v = -\frac{1}{2}c with respect to the pursuit car.

Now, according to the Galileo

the velocity of the bullet in the original frame of reference (u') will be

u' = u - v

on substituting the values we get

u' = \frac{1}{3}c-(-\frac{1}{2}c)

or

u' = \frac{1}{3}c+\frac{1}{2}c

or

u' = \frac{5}{6}c

since this velocity ( \frac{5}{6}c) is greater than the ( \frac{3}{4}c)

hence,

<u>the bullet will hit</u>

Now, according to the Einstein theory

the velocity of the bullet in the original frame of reference (u') will be

u'=\frac{u-v}{1-\frac{uv}{c^2}}

on substituting the values we get

u'=\frac{\frac{1}{3}c-\frac{1}{2}c}{1-\frac{\frac{1}{3}c\times \frac{1}{2}c}{c^2}}

or

u'=\frac{\frac{5}{6}c}{1-\frac{1}{6}}

or

u'=\frac{5}{7}c

since,

u'=\frac{5}{7}c is less than  ( \frac{3}{4}c), this means that the bullet will not hit

7 0
4 years ago
Ballet position which feet turned out
Dmitry [639]
Although all ballet positons involve turned out feet, the simplest one is first position. Heels are touching and toes face out, as far away from each other as possible (close to 180 degrees of rotation).
8 0
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The planets Hox and Blox are near each other in the Dorgon system. The Dorgons have very advanced technology, and a Dorgon scien
dexar [7]
<h2>Answer: Decreasing the distance between Hox and Blox, increasing the mass of Hox, or increasing the mass of Hox and Blox. </h2>

Explanation:

According to the law of universal gravitation:

F=G\frac{m_{1}m_{2}}{r^2}  

Where:  

F is the module of the attraction force exerted between both planets  

G is the universal gravitation constant.  

m_{1} and m_{2} are the masses of both planets.  

r is the distance between both planets.

As we can see, the gravity force is directly proportional to the mass of the bodies and inversely proportional to the square of the distance that separates them.

In other words:

If we decrease the distance between both planets (Hox and Blox), the gravitational pull between them will increase.  

On the other hand, if we keep the distance between Hox and Blox, but we increase the mass of one of them, or increase the mass of both, the gravitational pull between them will also increase.

7 0
3 years ago
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What is an Electrical transformer?​
Airida [17]

Answer:

A transformer is a passive electrical device that transfers electrical energy from one electrical circuit to another, or multiple circuits.

Explanation:

Hope it helps

5 0
3 years ago
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When you throw a ball, the work you do to accelerate it equals the kinetic energy the ball gains. If you do twice as much work w
aniked [119]

Answer:

No. Twice as much work will give the ball twice as much kinetic energy. But since KE is proportional to the speed squared, the speed will be sqrt{2} times larger.

Explanation:

The work done on the ball is equal to the kinetic energy gained by the ball:

W=K

So when the work done doubles, the kinetic energy doubles as well:

2W = 2 K

However, the kinetic energy is given by

K=\frac{1}{2}mv^2

where

m is the mass of the ball

v is its speed

We see that the kinetic energy is proportional to the square of the speed, v^2. We can rewrite the last equation as

v=\sqrt{\frac{2K}{m}}

which also means

v=\sqrt{\frac{2W}{m}}

If the work is doubled,

W'=2W

So the new speed is

v'=\sqrt{\frac{2(2W)}{m}}=\sqrt{2}\sqrt{\frac{2W}{m}}=\sqrt{2} v

So, the speed is \sqrt{2} times larger.

5 0
3 years ago
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