The solubility of a gas is .55 g/l at 8.0 atm pressure. what will be the solubility of the gas at 5.0 atm partial pressure?
1 answer:
Henry's law states that:
P1/C1 = P2/C2
Where P = Pressure, and C = Solubility
In this case, P1 = 8.0 atm, C1 = 0.55 g/l, P2 = 5.0 atm, C2 =??
Therefore,
C2 = (P2*C1)/P1 = (5*0.55)/8 = 0.344 g/l
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