C + H2O -> H2 + CO
n(C) = 15.9/12 = 1.325 (mol)
=> n(H2) = 1.325 mol
We have:
PV = nRT
=> V = (nRT)/P
(R = 22.4/273 = 0.082)
V = (1.325 x 0.082 x 360)/1 = 39.114 (L)
Answer:- 1467 K
Solution:- It asks to calculate the kelvin temperature of the light bulb. Looking at the given info, it is based on ideal gas law equation, PV=nRT.
Given: 
V = 75.0 mL = 0.0750 L
P = 116.8 kPa
We know that, 101.325 kPa = 1 atm
So, 
= 1.15 atm
R is universal gas constant and it's value is
.
T = ?
Let's plug in the values in the equation and solve it for T.

0.08625 = 0.00005878(T)

T = 1467 K
So, the temperature of the light bulb would be 1467 K.
Since the oxygen likes to hog all the electrons, it gives the hydrogen molecules a slight positive charge and the itself a slightly negative charge.
Positive attracts negative, so there is some sort of attraction between water molecules, though a weak one.
Answer:
It reflects light from one mirror to the second mirror so the second mirror reflects both the light and the image to the users eye.
Explanation: