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Mekhanik [1.2K]
3 years ago
8

Competitive pressures stemming from the threat of entry are stronger when

Physics
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

Industries outlook is uncertain

Explanation:

Competitive pressures stemming from the threat of entry are stronger when the industry's outlook is uncertain or highly risky, entry barriers are low, and very few existing industry members are looking to expand their market reach by entering product segments or geographic areas where they currently do not have a presence. entry barriers are low, the pool of entry candidates is large, and existing industry members are earning good profits. there are fewer than 10 entry candidates with the potential to hurdle the industry's barriers to entry. t is difficult or costly for a customer to switch to a new brand, the total dollar investment needed to enter the market successfully exceeds $5 million, and existing governmental regulations impose significant cost and compliance burdens on industry members. buyers have strong brand preferences and high degrees of loyalty to their preferred brand and when it takes new entrants less than 5 years to secure attractive amounts of space on retailers' shelves and build a well-recognized brand name.

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Two horses, Thunder and Misty, are accelerating a wagon 1.3 m/s2. The force of friction is 75 N. Thunder is pulling with a force
just olya [345]

Answer:

1327 kg

Explanation:

So the net force exerted on the wagon would be the sum of forces from 2 horses subtracted by friction force

F = 1000 + 800 - 75 = 1725 N

This force results in an acceleration of a = 1.3 m/s2. We can use Newton's 2nd law to calculate the mass of the wagon

F = ma

m = F / a = 1725 / 1.3 \approx 1327 kg

3 0
3 years ago
Batman chased the joker on his batbike for 20 minutes, traveling at the speed of 30 kilometers per minute. How far did Batman go
AURORKA [14]

Answer:

123 kilometer

Explanation:

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8 0
3 years ago
An electric wall clock has a second hand 15 cm long. at the tip of his hand, what is the magnitude of the velocity?
Mila [183]

The velocity of the tip of the second hand is 0.0158 m/s

Explanation:

First of all, we need to calculate the angular velocity of the second hand.

We know that the second hand completes one full circle in

T = 60 seconds

Therefore, its angular velocity is:

\omega = \frac{2\pi}{T}=\frac{2\pi}{(60)}=0.105 rad/s

Now we can calculate the velocity of a point on the tip of the hand by using the formula

v=\omega r

where

\omega=0.105 rad/s is the angular velocity

r = 15 cm = 0.15 m is the radius of the circle (the distance of the point from the centre of rotation)

Substituting,

v=(0.105)(0.15)=0.0158 m/s

Learn more about angular motion here:

brainly.com/question/9575487

brainly.com/question/9329700

brainly.com/question/2506028

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7 0
3 years ago
A 2 kg ball is dropped above the surface of Planet X. If the gravitational field strength at the surface of Planet X is 5 N/kg,
Trava [24]

Given data:

* The mass of the ball is 2 kg.

* The gravitational field strength at the surface of planet X is 5 N/kg.

Solution:

The weight of the ball on the planet X is,

W=ma

where m is the mass of ball, a is the gravitational field strength,

Substituting the known values,

\begin{gathered} W=2\times5 \\ W=10\text{ N} \end{gathered}

Thus, the weight of the ball on the surface of planet X is 10 N.

3 0
1 year ago
If the elephant were then allowed to fall straight down, how fast would it be moving when it landed back on the ground?
Oxana [17]

Answer:

0 mph because it is probably dead

6 0
3 years ago
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