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Ainat [17]
3 years ago
7

Wich of the following is an example of a cottonwood tree maintaining homeostasis

Chemistry
1 answer:
aleksley [76]3 years ago
8 0
The answer I believe would be A
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On the basis of oxidation number consideration which of the following does not react with molecular oxygen no ,n2o,so2,so3,p4o6
sesenic [268]
N oxidation number in N₂O = 1
S oxidation number in SO₂ = 4
S oxidation number in SO₃ = 6
P oxidation number in P₄O₆ = 3
Therefore, the Sulfur in SO₃ will not react with molecular oxygen as Sulfur is already using all of its valence electrons in bonding.
8 0
3 years ago
Compare and contrast the molecular activity of solids, liquids, and gases.​
cupoosta [38]

Answer:

The molecules in a solid are close together and they vibrate in place. The molecules in a liquid move quickly and farther apart from eachother. The particles in a gas move freely at high speeds and slide past eachother.

5 0
3 years ago
A sample of helium gas has a volume of 1.50 L at 159 K and 5.00 atm. When the gas is compressed to 0.200 L at 50.0 atm, the temp
Brums [2.3K]

Answer:

ghdtgfgrdvreeeegrwwggegteefewqrwefrwerrftrtdsfgyuytfgererdf

Explanation:

The given data is as follows.

     V_{1} = 1.50 L,    T_{1} = 159 K,

      P_{1} = 5.00 atm,   V_{2} = 0.2 L,

       T_{2} = ?,       P_{2} = 50.0 atm  

And, according to ideal gas equation,  

               \frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Hence, putting the given values into the above formula to calculate the value of final temperature as follows.          

 \frac{5.0 atm \times 1.50 L}{159 K} = \frac{5 atm \times 0.2 L}{T_{2}}

            T_{2} = 21.27 K

Thus, we can conclude that the final temperature is 21.27 K .

5 0
3 years ago
11.2 L of gas at a temperature of 25°C are held at a pressure of 1.1 atm. How many moles of gas are contained in the sample?
AysviL [449]
<span>0.5035 so go with .50 moles.
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5 0
3 years ago
How many moles of ba(oh)2 are present in 275 ml of 0.200 m ba(oh)2?
DENIUS [597]
You have to put your attention to the unit of concentration. It is expressed in terms of molarity, which is represented in M. It is the number of moles solute per liter solution. So, you simply have to multiply the molarity with the volume in liters.

Volume = 275 mL * 1 L/1000 mL = 0.275 L
<em>Moles Ba(OH)₂ = (0.200 M)(0.275 L) = 0.055 mol</em>
6 0
4 years ago
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