<span>Answer:
Benzylic radical . First Br radicals are produced which strip off a H- from the methyl group. The benzylic radical the reacts with Br2 to form benzylic bromide and another Br radical.</span>
Answer: 46.6 grams
Explanation:
Given : density of hexane = 0.660 g/ml
volume of hexane = 20 ml
Mass of hexane =
moles of hexane =
According to stoichiometry :
2 moles of hexane reacts with 19 moles of oxygen
Thus 0.14 moles hexane will react with = moles of oxygen
Mass of oxygen =
Thus minimum mass of oxygen required for the complete reaction of 20.0 mL of hexane is 46.6 grams.
Cyclopentane is NOT an isomer of pentane.
Isomers must have the same molecular formula.
The molecular formula of pentane is C₅H₁₂, while the molecular formula of cyclopentane is C₅H₁₀.
The two molecules cannot be isomers.
Answer:
Moles
Explanation:
Mole is used to describes the amount of matter. The one mole of every substance have different mass, because every matter has different mass. The one mole of substance is equal to the molar mass of that substance.
The molar mass of substance is the mass in gram in one mole and it is represented by g/mol.
For example:
The molar mass of oxygen is 16 g/mol. If we take 16 g of oxygen we would say we taken one mole of oxygen. If we take 32 g of oxygen than it is describe as two mole of oxygen.
Consider the following reaction:
2H₂ + O₂ → 2H₂O
In this reaction two mole of hydrogen gas combine with one mole of oxygen and produce two moles of water.
Answer:
4.96E-8 moles of Cu(OH)2
Explanation:
Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.
Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.
This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:
In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":
The expression for Kps is:
The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.
"s" is the soluble quantity of Cu(OH)2.
The solution for this third grade equation is
Now, let us calculate the moles in 1 L: