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Salsk061 [2.6K]
3 years ago
11

The work-energy theorem states that a force acting on a particle as it moves over a ______ changes the ______ energy of the part

icle if the force has a component parallel to the motion. Choose the best answer to fill in the blanks above: Choose the best answer to fill in the blanks above: distance / potential distance / kinetic vertical displacement / potential none of the above
Physics
2 answers:
omeli [17]3 years ago
8 0

Answer:

The work-energy theorem states that a force acting on a particle as it moves over a <u>distance</u> changes the <u>kinetic</u> energy of the particle if the force has a component parallel to the motion.

Explanation:

The correct answer is presented below and all reasons are presented to explain all facts:

The work-energy theorem states that a force acting on a particle as it moves over a <u>distance</u> changes the <u>kinetic</u> energy of the particle if the force has a component parallel to the motion.

Reasons:

According to the Work-Energy Theorem, the work done on a particle (W) equals the change in its kinetic energy (\Delta K). That is:

W = \Delta K (1)

By definition of work we expand this definition:

\oint \vec F\,\bullet\,d\vec s = \Delta K (2)

Where:

\vec F - Vector force.

\vec s - Vector travelled distance.

And by definition of dot product we conclude that:

\int\limits_{A}^{B}{\|\vec F\|\cdot \|d\vec{s}\|\cdot \cos \phi} = \Delta K

Where:

\|\vec F\| - Magnitude of the vector force.

\|d\vec s\| - Magnitude of the differential of the vector travelled distance.

\phi - Angle between vectors, measured in sexagesimal degrees.

A, B - Initial and final position of the particle.

From this expression we infer that change in kinetic energy is maximum if and only if \phi = 0^{\circ} in every point of the path travelled by the particle. In addition, change in kinetic energy occurs when component of force parallel to path is not zero.

Kitty [74]3 years ago
4 0

Answer: The work-energy theorem states that a force acting on a particle as it moves over a DISTANCE changes the KINETIC energy of the particle if the force has a component parallel to the motion.

Explanation:

The work- energy theorem states that the work done when forces act on particles as it moves over a distance is equal to the change in Kinetic energy of the particle if the force has a component parallel to the motion. To express this definition an equation is used:

W= ∆K.E =(final K. E. - initial K. E)

Therefore W= ½mv²(final) - ½mv²(initial)

Where W is work done by net force and

K.E ( final minus the initial) is the particle change in Kinetic Energy.

According to this theorem, when an object slows down, its final kinetic energy is less than its initial kinetic energy, the change in its kinetic energy is negative, and so is the net work done on it. If an object speeds up, the net work done on it is positive. When calculating the net work, you must include all the forces that act on an object.

This theorem also shows that since work done on a particle can lead to change in its kinetic energy, it implies that work can transfer energy from one form to another.

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Which of the following describe advantages of using radio waves over other electromagnetic waves to transmit information to Eart
Whitepunk [10]

The correct options are:

D

"Radio waves have a lower frequency, which makes them safer for humans."

B

"Radio waves take less energy to produce."

<h3>Why do we radio waves over other electromagnetic waves to transmit information to Earth? </h3>

Radio waves are electromagnetic waves with frequencies on the range from 10 KHz to 10 THz.

Now, remember that all electromagnetic waves have the same speed, which is the speed of light, and the energy of a wave is proportional to its frequency.

Particularly, we can see that radio waves have small frequencies (smaller than infrared light) so these waves carry very little energy.

With that in mind, the correct options are.

D

"Radio waves have a lower frequency, which makes them safer for humans."

B

"Radio waves take less energy to produce."

These are the two main reasons of why we use radio waves.

If you want to learn more about electromagnetic waves.

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1 year ago
Which of the following is a densit-independent factor
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3 years ago
if a 0.040-kg stone is whirled horizontally on the end of a 60-m string at a speed of 4.4 m/s, what is the centripetal force ? *
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Answer:

0.013N

Explanation:

F=\frac{mv^{2} }{r}

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2 years ago
Mass Center Determine the coordinates (x, y) of the center of mass of the area in blue in the figure below. Answers: x=(3)/(8)a
Naya [18.7K]

Explanation:

The x and y coordinates of the center of mass are:

xcm = ∫ x dm / m = ∫ x ρ dA / ∫ ρ dA

ycm = ∫ y dm / m = ∫ y ρ dA / ∫ ρ dA

Assuming uniform density, the center of mass is also the center of area.

xcm = ∫ x dA / ∫ dA = ∫ x y dx / A

ycm = ∫ y dA / ∫ dA = ∫ ½ y² dx / A

First, let's find the area:

A = ∫ y dx

A = ∫₀ᵃ (-h/a² x² + h) dx

A = -⅓ h/a² x³ + hx |₀ᵃ

A = -⅓ h/a² (a)³ + h(a)

A = ⅔ ha

Now, let's find the x coordinate of the center of mass:

xcm = ∫ x y dx / A

xcm = ∫₀ᵃ x (-h/a² x² + h) dx / (⅔ ha)

xcm = ∫₀ᵃ (-h/a² x³ + hx) dx / (⅔ ha)

xcm = (-¼ h/a² x⁴ + ½ hx²) |₀ᵃ / (⅔ ha)

xcm = (-¼ h/a² (a)⁴ + ½ h(a)²) / (⅔ ha)

xcm = (¼ ha²) / (⅔ ha)

xcm = ⅜ a

Next, we find the y coordinate of the center of mass:

ycm = ∫ y² dx / A

ycm = ∫₀ᵃ ½ (-h/a² x² + h)² dx / (⅔ ha)

ycm = ∫₀ᵃ ½ (h²/a⁴ x⁴ − 2h²/a² x² + h²) dx / (⅔ ha)

ycm = ½ (⅕ h²/a⁴ x⁵ − ⅔ h²/a² x³ + h² x) |₀ᵃ / (⅔ ha)

ycm = ½ (⅕ h²/a⁴ (a)⁵ − ⅔ h²/a² (a)³ + h² (a)) / (⅔ ha)

ycm = ½ (⁸/₁₅ h²a) / (⅔ ha)

ycm = ⅖ h

6 0
3 years ago
Standing on a mountain, you look towards another mountain 6.00 km away, on which there are two persons standing 1.00 meter apart
allsm [11]

Answer:

No.

Explanation:

We shall solve this problem by calculating the resolving power of eye for given wavelength

Resolving Power of eye = \frac{1.22\lambda }{D}

Where λ is wave length of light and D is diameter of eye.

λ is 600 nm and D is 3.5 mm . Put these values in the given formula

Resolving Power = \frac{1.22\times 600\times 10^{-9} }{3.5\times 10^{-3}}\\

=209.14 \times 10^{-6}radian

From the formula

Φ = \frac{L}{D}[/tex]

Where Ф is resolving power . If L be distance between two points that can be resolved at distance D. D is 6 km or 6000 m .

209.14  \times 10^{-6}=\frac{L}{6000}\\

L= 1.254 m

So minimum distance that can be resolved is 1.254 m.

5 0
3 years ago
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