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Salsk061 [2.6K]
3 years ago
11

The work-energy theorem states that a force acting on a particle as it moves over a ______ changes the ______ energy of the part

icle if the force has a component parallel to the motion. Choose the best answer to fill in the blanks above: Choose the best answer to fill in the blanks above: distance / potential distance / kinetic vertical displacement / potential none of the above
Physics
2 answers:
omeli [17]3 years ago
8 0

Answer:

The work-energy theorem states that a force acting on a particle as it moves over a <u>distance</u> changes the <u>kinetic</u> energy of the particle if the force has a component parallel to the motion.

Explanation:

The correct answer is presented below and all reasons are presented to explain all facts:

The work-energy theorem states that a force acting on a particle as it moves over a <u>distance</u> changes the <u>kinetic</u> energy of the particle if the force has a component parallel to the motion.

Reasons:

According to the Work-Energy Theorem, the work done on a particle (W) equals the change in its kinetic energy (\Delta K). That is:

W = \Delta K (1)

By definition of work we expand this definition:

\oint \vec F\,\bullet\,d\vec s = \Delta K (2)

Where:

\vec F - Vector force.

\vec s - Vector travelled distance.

And by definition of dot product we conclude that:

\int\limits_{A}^{B}{\|\vec F\|\cdot \|d\vec{s}\|\cdot \cos \phi} = \Delta K

Where:

\|\vec F\| - Magnitude of the vector force.

\|d\vec s\| - Magnitude of the differential of the vector travelled distance.

\phi - Angle between vectors, measured in sexagesimal degrees.

A, B - Initial and final position of the particle.

From this expression we infer that change in kinetic energy is maximum if and only if \phi = 0^{\circ} in every point of the path travelled by the particle. In addition, change in kinetic energy occurs when component of force parallel to path is not zero.

Kitty [74]3 years ago
4 0

Answer: The work-energy theorem states that a force acting on a particle as it moves over a DISTANCE changes the KINETIC energy of the particle if the force has a component parallel to the motion.

Explanation:

The work- energy theorem states that the work done when forces act on particles as it moves over a distance is equal to the change in Kinetic energy of the particle if the force has a component parallel to the motion. To express this definition an equation is used:

W= ∆K.E =(final K. E. - initial K. E)

Therefore W= ½mv²(final) - ½mv²(initial)

Where W is work done by net force and

K.E ( final minus the initial) is the particle change in Kinetic Energy.

According to this theorem, when an object slows down, its final kinetic energy is less than its initial kinetic energy, the change in its kinetic energy is negative, and so is the net work done on it. If an object speeds up, the net work done on it is positive. When calculating the net work, you must include all the forces that act on an object.

This theorem also shows that since work done on a particle can lead to change in its kinetic energy, it implies that work can transfer energy from one form to another.

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What is the highest degrees above the horizon the moon ever gets during the year in the Yakima Valley ?
Ivahew [28]

The trickiest part of this problem was making sure where the Yakima Valley is.
OK so it's generally around the city of the same name in Washington State.

Just for a place to work with, I picked the Yakima Valley Junior College, at the
corner of W Nob Hill Blvd and S16th Ave in Yakima.  The latitude in the middle
of that intersection is 46.585° North.  <u>That's</u> the number we need.

Here's how I would do it:

-- The altitude of the due-south point on the celestial equator is always
(90° - latitude), no matter what the date or time of day.

-- The highest above the celestial equator that the ecliptic ever gets
is about 23.5°. 

-- The mean inclination of the moon's orbit to the ecliptic is 5.14°, so
that's the highest above the ecliptic that the moon can ever appear
in the sky.

This sets the limit of the highest in the sky that the moon can ever appear.

90° - 46.585° + 23.5° + 5.14° = 72.1° above the horizon .

That doesn't happen regularly.  It would depend on everything coming
together at the same time ... the moon happens to be at the point in its
orbit that's 5.14° above ==> (the point on the ecliptic that's 23.5° above
the celestial equator).

Depending on the time of year, that can be any time of the day or night.

The most striking combination is at midnight, within a day or two of the
Winter solstice, when the moon happens to be full.

In general, the Full Moon closest to the Winter solstice is going to be
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5 0
3 years ago
When Woods hits a 0.04593 kg golf ball, the golf ball is usually traveling around 281 kilometers per hour. What average force do
Semenov [28]

Answer:

128.9 N

Explanation:

The force exerted on the golf ball is equal to the rate of change of momentum of the ball, so we can write:

F=\frac{\Delta p}{\Delta t}

where

F is the force

\Delta p is the change in momentum

\Delta t=0.030 s is the time interval

The change in momentum can be written as

\Delta p = m(v-u)

where

m = 0.04593 kg is the mass of the ball

u = 0 is the initial velocity of the ball

v=281 km/h =78.1 m/s is the final velocity of the ball

Substituting into the original equation, we find the force exerted on the golf ball:

F=\frac{m(v-u)}{\Delta t}=\frac{(0.04593)(78.1-0)}{0.030}=128.9 N

7 0
3 years ago
A stone is thrown horizontally at 60.0 m/sm/s from the top of a very tall cliff. Calculate its horizontal position and vertical
svp [43]

Answer:

X-Positions:                                         Y-Positions

x(0) = 0                                                   y(0) = 0

x(2) = 120 m                                           y(2) = 19.6 m

x(4) = 240 m                                          y(4) = 78.4 m

x(6) = 360 m                                          y(6) = 176.4 m

x(8) = 480 m                                          y(8) = 313 m

x(10) = 600m                                         y (10) = 490 m

Explanation:

X-Positions

  • First, we choose to take the horizontal direction as our x-axis, and the positive x-axis as positive.
  • After being thrown, in the horizontal direction, no external influence acts on the stone, so it will continue in the same direction at the same initial speed of 60. 0 m/s
  • So, in order to know the horizontal position at any time t, we can apply the definition of average velocity, rearranging terms, as follows:

       x = v_{ox} * t = 60.0 m/s * t(s)

  • It can be seen that after 2 s, the displacement will be 120 m, and each 2 seconds, as the speed is constant, the displacement will increase in the same 120 m each time.

Y-Positions

  • We choose to take the vertical direction as our y-axis, taking the downward direction as our positive axis.
  • As both axes are  perpendicular each other, both movements are independent each other also, so, in the vertical direction, the stone starts from rest.
  • At any moment, it is subject to the acceleration of gravity, g.
  • As the acceleration is constant, we can find the vertical displacement (taking the  height of the cliff as the initial reference level), using the following kinematic equation:

       y = \frac{1}{2} * g* t^{2} = \frac{1}{2} * 9.8 m/s2 * t(s)^{2}

  • Replacing by the values of t, we get the following vertical positions, from the height of the cliff as y = 0:
  • y(2) = 2* 9.8 m/s2 = 19.6 m
  • y(4) = 8* 9.8 m/s2 = 78.4 m
  • y(6) = 18*9.8 m/s2 = 176.4 m
  • y(8) = 32*9.8 m/s2 = 313.6 m
  • y(10)= 50 * 9.8 m/s2 = 490.0 m
5 0
3 years ago
1. For a reaction to occur, energy must be
amm1812

For a reaction to occur, energy must be absorbed to break chemical bonds

<u>Explanation:</u>

Reactions can be classified as chemical reaction, nuclear reaction, thermal reaction. So in these three reaction types, the nature of energy will only be varying.

But in order to execute a reaction, there should be breaking of existing bonds and then formation of new bonds. So for breaking of the bonds of reactants, energy should be absorbed from the surrounding.

Then the extra energy will be released after forming the products. Thus, the process of absorption of energy will lead to endothermic process and the process of releasing of energy will lead to exothermic reaction. So for a reaction to occur, energy must be absorbed to break the chemical bonds.

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