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Salsk061 [2.6K]
3 years ago
11

The work-energy theorem states that a force acting on a particle as it moves over a ______ changes the ______ energy of the part

icle if the force has a component parallel to the motion. Choose the best answer to fill in the blanks above: Choose the best answer to fill in the blanks above: distance / potential distance / kinetic vertical displacement / potential none of the above
Physics
2 answers:
omeli [17]3 years ago
8 0

Answer:

The work-energy theorem states that a force acting on a particle as it moves over a <u>distance</u> changes the <u>kinetic</u> energy of the particle if the force has a component parallel to the motion.

Explanation:

The correct answer is presented below and all reasons are presented to explain all facts:

The work-energy theorem states that a force acting on a particle as it moves over a <u>distance</u> changes the <u>kinetic</u> energy of the particle if the force has a component parallel to the motion.

Reasons:

According to the Work-Energy Theorem, the work done on a particle (W) equals the change in its kinetic energy (\Delta K). That is:

W = \Delta K (1)

By definition of work we expand this definition:

\oint \vec F\,\bullet\,d\vec s = \Delta K (2)

Where:

\vec F - Vector force.

\vec s - Vector travelled distance.

And by definition of dot product we conclude that:

\int\limits_{A}^{B}{\|\vec F\|\cdot \|d\vec{s}\|\cdot \cos \phi} = \Delta K

Where:

\|\vec F\| - Magnitude of the vector force.

\|d\vec s\| - Magnitude of the differential of the vector travelled distance.

\phi - Angle between vectors, measured in sexagesimal degrees.

A, B - Initial and final position of the particle.

From this expression we infer that change in kinetic energy is maximum if and only if \phi = 0^{\circ} in every point of the path travelled by the particle. In addition, change in kinetic energy occurs when component of force parallel to path is not zero.

Kitty [74]3 years ago
4 0

Answer: The work-energy theorem states that a force acting on a particle as it moves over a DISTANCE changes the KINETIC energy of the particle if the force has a component parallel to the motion.

Explanation:

The work- energy theorem states that the work done when forces act on particles as it moves over a distance is equal to the change in Kinetic energy of the particle if the force has a component parallel to the motion. To express this definition an equation is used:

W= ∆K.E =(final K. E. - initial K. E)

Therefore W= ½mv²(final) - ½mv²(initial)

Where W is work done by net force and

K.E ( final minus the initial) is the particle change in Kinetic Energy.

According to this theorem, when an object slows down, its final kinetic energy is less than its initial kinetic energy, the change in its kinetic energy is negative, and so is the net work done on it. If an object speeds up, the net work done on it is positive. When calculating the net work, you must include all the forces that act on an object.

This theorem also shows that since work done on a particle can lead to change in its kinetic energy, it implies that work can transfer energy from one form to another.

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A 2000 kg car experiences a braking force of 10000N and skids to a 14 m stop. What was the speed of the car just before the brak
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V = 11.83 m/s

Explanation:

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5 0
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A string that is under 54.0 N of tension has linear density 5.20 g/m . A sinusoidal wave with amplitude 2.50 cm and wavelength 1
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Answer:

8.89288275 m/s

Explanation:

F = Tension = 54 N

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A = Amplitude = 2.5 cm

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v=\sqrt{\frac{F}{\mu}}\\\Rightarrow v=\sqrt{\frac{54}{5.2\times 10^{-3}}}\\\Rightarrow v=101.90493\ m/s

Frequency is given by

f=\frac{v}{\lambda}\\\Rightarrow f=\frac{101.90493}{1.8}\\\Rightarrow f=56.61385\ Hz

Angular frequency is given by

\omega=2\pi f\\\Rightarrow \omega=2\pi 56.61385\\\Rightarrow \omega=355.71531\ rad/s

Maximum velocity of a particle is given by

v_m=A\omega\\\Rightarrow v_m=0.025\times 355.71531\\\Rightarrow v_m=8.89288275\ m/s

The maximum velocity of a particle on the string is 8.89288275 m/s

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2 years ago
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