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MrRissso [65]
3 years ago
11

Juan measured the temperature of salt water. He then added 273 to the measured value. Which conversion is Juan m

Physics
1 answer:
lara31 [8.8K]3 years ago
6 0

Degree Celsius to Kelvin

<u>Explanation</u>:

  • Two units of measuring temperature are Degree Celsius and Kelvin.
  • A measured value in degree Celsius can be converted to Kelvin by adding 273 to it. Here, Juan is doing that conversion - degree Celsius to Kelvin.
  • °C + 273 = K
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Tresset [83]

Answer: c is correct

Explanation: i did this

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Which of the following is one of the three main fuels that a star uses for fusion
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Hydrogen, helium, and carbon.
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Enunciado: Una bola se lanza verticalmente de la parte superior de un edificio con una velocidad inicial de 25 m/s. La bola impa
bearhunter [10]

Responder:

Explicación:

Usaremos la ecuación de movimiento para determinar la altura de la bola medida desde la parte superior del edificio.

Usando la ecuación para obtener la altura de caída

S = ut + 1 / 2gt²

u es la velocidad inicial = 25 m / s

g es la aceleración debida a la gravedad = 9,81 m / s²

t es el tiempo = 7 segundos

S es la altura de la caída

S = 25 (7) +1/2 (9,81) × 7²

S = 175 + 4,905 (49)

S = 175 + 240,345

S = 415,35 m

Esto significa que la pelota se elevó a 415,35 m de altura

7 0
3 years ago
A block of mass M slides down a frictionless plane inclined at an angle (theta) with the horizontal. The normal reaction force e
WINSTONCH [101]

Answer: N = Mgcos(theta)

Therefore, the Normal reaction force is equal to Mgcos(theta)

Explanation:

See attached for a sketch.

From the attachment.

.

N = normal reaction force on block

W = weight of the block

theta = angle of the inclined plane to the horizontal

From the sketch, we can see that

N is equal in magnitude but opposite direction to Wy

N = Wy

And

Wy = Wcos(theta)

Wx = Wsin(theta)

Then,

N = Wy = Wcos(theta)

But W = mass × acceleration due to gravity = mg

N = Mgcos(theta)

Therefore, the Normal reaction force is equal to Mgcos(theta)

7 0
3 years ago
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A 3 5m container is filled with 900 kg of granite (density of 2400 3 kg m/ ). The rest of the volume is air, with density equal
Elina [12.6K]

Complete question:

A 5-m³ container is filled with 900 kg of granite (density of 2400 kg/m3). The rest of the volume is air, with density equal to 1.15 kg/m³. Find the mass of air and the overall (average) specific volume.

Answer:

The mass of the air is 5.32 kg

The specific volume is 5.52 x 10⁻³ m³/kg

Explanation:

Given;

total volume of the container, V_t = 5 m³

mass of granite, m_g = 900 kg

density of granite, \rho _g = 2,400 kg/m³

density of air, \rho_a = 1.15 kg/m³

The volume of the granite is calculated as;

V_g = \frac{m_g}{ \rho_g}\\\\V_g = \frac{900 \ kg}{2,400 \ kg/m^3} \\\\V_g = 0.375 \ m^3

The volume of air is calculated as;

V_a = V_t - V_g\\\\V_a = 5 \ m^3  \ - \ 0.375 \ m\\\\V_a = 4.625 \ m^3

The mass of the air is calculated as;

m_a = \rho_a \times V_a\\\\m_a = 1.15 \ kg/m^3 \ \times \ 4.625 \ m^3\\\\m_a = 5.32 \ kg

The specific volume is calculated as;

V_{specific} = \frac{V_t}{m_g \ + \ m_a} = \frac{5 \ m^3}{900 \ kg \ + \ 5.32\ kg} = 5.52 \times 10^{-3} \ m^3/kg

4 0
3 years ago
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