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MrRissso [65]
3 years ago
11

Juan measured the temperature of salt water. He then added 273 to the measured value. Which conversion is Juan m

Physics
1 answer:
lara31 [8.8K]3 years ago
6 0

Degree Celsius to Kelvin

<u>Explanation</u>:

  • Two units of measuring temperature are Degree Celsius and Kelvin.
  • A measured value in degree Celsius can be converted to Kelvin by adding 273 to it. Here, Juan is doing that conversion - degree Celsius to Kelvin.
  • °C + 273 = K
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A spring is hung from the ceiling. A 2.0-kg mass suspended hung from the spring extends it by 6.0 cm. A downward external force
Stolb23 [73]

The work done by force on a spring hung from the ceiling will be 1.67 J

Any two things with mass are drawn together by the gravitational pull. We refer to the gravitational force as attractive because it consistently seeks to draw masses together rather than pushing them apart.

Given that a spring is hung from the ceiling with a 2.0-kg mass suspended hung from the spring extends it by 6.0 cm and a downward external force applied to the mass extends the spring an additional 10 cm.

We need to find the work done by the force

Given mass is of 2 kg

So let,

F = 2 kg

x = 0.1 m

Stiffness of spring = k = F/x

k = 20/0.006 = 333 n/m

Now the formula to find the work done by force will be as follow:

Workdone = W = 0.5kx²

W = 0.5 x 333 x 0.1²

W = 1.67 J

Hence the work done by force on a spring hung from the ceiling will be 1.67 J

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8 0
2 years ago
g calculate the effectiveness radiation dosage in sieverts for a 79 kg person who is exposed 6.8x10^9
Elza [17]

Answer:

The answer is "\bold{dosage = 0.031 rem}"

Explanation:

please find the complete question in the attached file.

Given value:

m = 79\  kg  \\\\n = 3.4 \times  10^9 \\\\E = 5.5  \times  10^{-13} \\\\ RBE = 15

\to E = n E\\

        = 3.4  \times  10^9  \times  5.5  \times  10^{-13} \\\\      = 1.87 \times  10^{-3}

\to E(absorbed) = 1.87  \times 10^{-3}  \times  0.87 = 1.63  \times  10^{-3}

calculating the radiation absorbed per kg:

= \frac{1.63  \times  10^{-3}}{79}  \\\\ = 2.06  \times  10^{-5} \\\\ = 0.00206 \  rad

\to Dosage = 0.00206  \times  15 \\

                 = 0.031 \ \ rem

4 0
3 years ago
What is the potential energy of a 0.5 kg object sitting on a shelf that is 1.5 meters high?
Archy [21]
Gravitational potential energy=mass x height X gravitational field strength
=0.5 x1.5 x9.7(gravity)=7.275J
5 0
3 years ago
Read 2 more answers
What is the definition of
marysya [2.9K]
Upper fixed point is a temperature of stem from water boiling and standards atmospheric pressure

Lower fixed point is the temperature of pure melting ice.
8 0
3 years ago
A proton in a uniform electric field moves along a straight line with constant acceleration. Starting from rest it attains a vel
Sav [38]

a) The acceleration of the proton is 5.0\cdot 10^{13} m/s^2

b) The time required to reach the given velocity is 2\cdot 10^{-8}s

Explanation:

a)

This is a motion at constant acceleration, so we can use the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the proton in this problem, we have:

v=1,000,000 m/s is the final velocity

u=0 is the initial velocity (it starts from rest)

s = 0.01 m is the distance covered

Solving for a, we find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{(1,000,000)^2-0}{2(0.01)}=5.0\cdot 10^{13} m/s^2

b)

For this part, we can use the following suvat equation instead:

v=u+at

where:

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken for the velocity to change from u to v

We have here the following data:

v=1,000,000 m/s is the final velocity

u=0 is the initial velocity (it starts from rest)

a=5.0\cdot 10^{13} m/s^2

Solving for t, we find

t=\frac{v-u}{a}=\frac{1,000,000}{5.0\cdot 10^{13}}=2\cdot 10^{-8}s

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