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Deffense [45]
3 years ago
14

What is the mass of the beaker plus water

Chemistry
1 answer:
grigory [225]3 years ago
7 0
To find the mass of the water, you will first need to find the mass of a dry 100 mL beaker.-------51.377g 
<span>Next, find the mass of the 100 mL beaker containing your water sample. ------------------------ 101.23g  hope this helps :()</span>
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Collectiveness leads to a good society? how​
ivann1987 [24]

Answer:

A good society has a transparent talk, they share all matters related to the society, hence everyone knows what's going on. This is why collectiveness leads to a good society.

If my answer helped, kindly mark me as the brainliest!!

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8 0
2 years ago
recommend an element use to fill bottles that contain ancient paper. the element should be a gas at room temperature, should be
Eduardwww [97]

Okay so we are given these requirements:

element which can be used to stuff bottles that enclose ancient paper
must be a gas at room temperature
must be denser than helium
must not react with other elements

 

The only element that comes into my mind is:

<span>Argon</span>

6 0
3 years ago
Why is there a difference in the conductivity of pure solid NaC1 and of the 1.0 M NaC1 soulution
Basile [38]
That would be cause part of the sodium is pure and that means it still kind of has it properties when it was an element and that its i think.
7 0
3 years ago
A piece of lithium is placed on the surface of some water in a beaker. hydrogen is given off. Lithium hydroxide is formed. What
Gala2k [10]
<span>A piece of lithium is placed on the surface of some water in a beaker. Hydrogen is given off and Lithium hydroxide is formed. The word equation would be as follows:
</span>

lithium<span> + </span>water<span>→ </span>lithium hydroxide<span> + </span>hydrogen

Hope this answers the question. Have a nice day.
8 0
3 years ago
Calculate e°cell for a silver-aluminum cell in which the cell reaction is al(s) + 3ag+(aq) → al3+(aq) + 3ag(s) –2.46 v 0.86 v –0
tekilochka [14]
When E° cell is an electrochemical cell which comprises of two half cells.
 
So,

when we have the balanced equation of this half cell :

Al3+(aq) + 3e- → Al(s)   and E°1 = -1.66 V 

and we have  also this balanced equation of this half cell :

Ag+(aq)  + e- → Ag(s)  and E°2 = 0.8 V 

so, we can get E° in Al(s) + 3Ag (aq) → Al3+(aq) + 3Ag(s)

when E° = E°2 - E°1

∴E° =0.8 - (-1.66)

      = 2.46 V

∴ the correct answer is 2.46 V




6 0
3 years ago
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