Q= mcΔT
1623 = 33.69g x c x (110.8 - 29.4)
1623 = 2742.366 g•°C x c
c = 0.59j/g•°C
Answer:
False
Explanation:
The values of the principal quantum number range from 1- infinity. This implies that there is no such thing as an energy level with n=0.
Hence this can not be an acceptable set of quantum numbers when n=0.
I can't see the picture, but in general, I believe it is in dropping from the first energy level above the ground state, to the ground state.
Answer:
21H deuterium (D), 31H is tritium (T), 11H is hydrogen
Explanation:
11H: it has the greatest abundance, it has only one proton (it does not have neutrons).
21H (D): it has a proton and a neutron in its nucleus.
31H (T): it has a proton and two neutrons in its nucleus.
Remember that isotopes have the same atomic number, but a different mass number (elements in the number of neutrons differed).
Answer:
Average atomic mass of potassium based on these relative abundances
Explanation:
The atomic mass of this element will be equal to the sum of product of its three isotopic masses and its fractional abundance
For isotope I -
Mass of Potassium-39 
amu
Fractional abundance of Potassium-39 
%
Mass of Potassium-40 
amu
Fractional abundance of Potassium-40 
%
Mass of Potassium-41 
amu
Fractional abundance of Potassium-41 
%
Average atomic mass of potassium based on these relative abundances
