Answer:
The person will travel 24 meters.
Explanation:
Distance = Rate * TIme
Distance = d = ?
Rate = r = 6 m/s
Time = t = 4 seconds
d = r*t = (6 m/s)*(4 seconds)
d = 24 m
**Note that the units (m/s) and (s/1) cancel to leave the answer in meters, the desired unit**
Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
P.E. = 5880
Kinetic Energy (Final One) = 1/2 mv²
K.E. = 1/2 * 60 * (10)²
K.E. = 6000/2
K.E. = 3000
Lost Energy = 5880 - 3000 = 2880 J
In short, Your Answer would be 2880 Joules
Hope this helps!
The type of ball is independent, as it doesn’t affect the experiment.
The car travels at a speed of 25m/s.
<u>Explanation:</u>
Given-
Mass, m = 1500kg
Coefficient of friction, μk = 0.47
Distance, x = 68m
Speed, s = ?
We know,
![Force, F = ma](https://tex.z-dn.net/?f=Force%2C%20F%20%3D%20ma)
and
F = μ X m X g
Therefore,
μ * m * g = m * a
μ * g = a
Let, g = 9.8m/s²
So,
![a = 0.47 * 9.8 m/s^2](https://tex.z-dn.net/?f=a%20%3D%200.47%20%2A%209.8%20m%2Fs%5E2)
![a = 4.606m/s^2](https://tex.z-dn.net/?f=a%20%3D%204.606m%2Fs%5E2)
We know,
![v^2 - u^2 = 2as](https://tex.z-dn.net/?f=v%5E2%20-%20u%5E2%20%3D%202as)
where, v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance
If the car comes to rest, the final velocity, v becomes 0.
So,
![u^2 = 2 * 4.606 * 68\\\\u^2 = 626.416m/s\\\\u = 25m/s](https://tex.z-dn.net/?f=u%5E2%20%3D%202%20%2A%204.606%20%2A%2068%5C%5C%5C%5Cu%5E2%20%3D%20626.416m%2Fs%5C%5C%5C%5Cu%20%3D%2025m%2Fs)
The car travels at a speed of 25m/s.
Answer:
0.05 cents per fl oz
Explanation:
0.95 divided by 20
0.0475 to the nearest cent 0.05