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Oduvanchick [21]
3 years ago
12

Do you know any of these?

Chemistry
1 answer:
jok3333 [9.3K]3 years ago
3 0
Mass can identify molecules and atoms
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#1: Jim, Jane, Ann, and Bill measure an object’s length, density, mass, and volume, respectively. Which student’s measurement mi
STatiana [176]
1. The <span>student with a measurement that might be in centimeters is A. Bill.
2. C</span><span>entimeters  in 0.05 kilometers is </span>C. 5,000
solution:
0.05 km x (1000 meters/ 1 km)
= 50 meters x (100 cm/ 1 meter) 
=5000 cm
7 0
3 years ago
Read 2 more answers
For metalloids on the periodic table, how do the group number and the period number relate?
Studentka2010 [4]

Answer : The correct option is A.

Explanation :

Metalloid : Metaloids are the elements whose properties lie between the metals and non-metals.

There are six commonly elements which are boron, silicon, germanium, arsenic, antimony and tellurium. The rare elements are polonium and astatine.

The relation between the group number and period number of metalloid is that the lower the group number, the lower the period numbers and the metalloids are found in a diagonal moving down from left to right in the periodic table.

5 0
3 years ago
Read 2 more answers
the temperature of a sample of water increases from 20celsius to 46.6celsius as it absorbs 5650 J of heat. what is the mass of t
Levart [38]

Answer:

m = 50.74 kg

Explanation:

We have,

Initial temperature of water is 20 degrees Celsius

Final temperature of water is 46.6 degrees Celsius

Heat absorbed is 5650 J

It is required to find the mass of the sample. The heat absorbed is given by the formula ad follows :

Q=mc\Delta T

c is specific heat of water, c = 4.186 J/g°C

So,

m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{5650}{4.186\times (46.6-20)}\\\\m=50.74\ kg

So, the mass of the sample is 50.74 kg.

8 0
3 years ago
(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2
maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ =  (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

5 0
3 years ago
What is the number of Cl atoms in a 784 gram pure sample of NC13?
LuckyWell [14K]

Answer:

idk

Explanation:

idk cool pee bee mee nee hee gee fee kee

5 0
3 years ago
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