All categories

3 years ago

The strength of an acid or base depends on the degree on of ionization in water. The graph represents a

Physics

2 answers:

raketka [301]3 years ago

6 0

Answer:

the answer is A - weak acid

Explanation:

Likurg_2 [28]3 years ago

5 0

HA in the graph represents a weak acid.

<h3>Explanation</h3>

Is HA an acid or a base?

Apply the Arrhenius Theory of Acids and Bases.

Acids ionize in water to produce $\text{H}^{+}$ (or equivalently $\text{H}_3\text{O}^{+}$ ) and a conjugate ion.
Bases ionize in water to produce $\text{OH}^{-}$ and a conjugate ion.

The equation in the picture shows that HA ionizes in water to produce $\text{H}_3\text{O}^{+}$ ions. By the Arrhenius Theory of acids and bases, HA is an acid.

Is HA a weak acid or a strong acid?

Both weak and strong Arrhenius acids ionize in water to produce $\text{H}^{+}$ (or equivalently $\text{H}_3\text{O}^{+}$ ) and a conjugate ion. However,

Strong acids ionize completely. There would be nearly no acid left in the solution. Expect arrows $\to$ ⇒ in only one direction in the equation.
Weak acids also ionize, but only partially. There would be plenty of acid left in the solution. Expect two-sided arrows like ⇔ and two-sided harpoons like $\rightleftharpoons$ in the equation.

As seen in the bar chart, there are plenty of HA left after ionization. HA ionizes only partially. Also, the equation shows a two-sided arrow. As a result, HA is a weak acid.

You might be interested in

The block brake consists of a pin-connected lever and friction block at B. The coefficient of static friction between the wheel

erastovalidia [21]

Answer:

Explanation:

8 0

3 years ago

Read 2 more answers

A projectile is launched from ground level at angle u and speed v0 into a headwind that causes a constant horizontal acceleratio

ale4655 [162]

Answer:

Explanation:

Given

Launch angle =u

Initial Speed is $v_0$

Horizontal acceleration is $a_x=a$

At maximum height velocity is zero therefore

$v_f=v_i-gt$

$0=v_0\sin u-gt$

$t=\frac{v_0\sin u}{g}$

Total time of flight $T=2t=\frac{2v_0\sin u}{g}$

During this time horizontal range is

$R=v_o\cos u\cdot 2t-\frac{a(2t)^2}{2}$

$R=\frac{2v_0^2\sin u\cos u}{g}-\frac{2av_0^2\sin ^u}{g^2}$

For maximum range $\frac{\mathrm{d} R}{\mathrm{d} u}=0$

$\frac{\mathrm{d} R}{\mathrm{d} u}=\frac{2v_0^2\cos 2u}{g}-\frac{4av_0^2\sin u\cos u}{g^2}$

$\frac{\mathrm{d} R}{\mathrm{d} u}=\frac{2v_0^2}{g}\left [ \cos 2u-\frac{a}{g}\sin 2u\right ]=0$

$\tan 2u=\frac{g}{a}$

$u=\frac{1}{2}tan ^{-1}\frac{g}{a}$

(b)If a =10% g

$a=0.1g$

thus $u=\frac{1}{2}tan^{-1}\frac{g}{0.1g}$

$u=42.14^{\circ}$

7 0

2 years ago

Plzzzzzzzzzz!!!!!!! Hurryyyyy

Scilla [17]

Answer:

student A or B

Explanation:

A common demonstration is to put a ringing alarm clock or bell in the bell jar, and when the vacuum is created, you can no longer hear the sound of the clock/bell.

The bell is connected to a lab pack or batteries and rung to show pupils it can be heard under normal circumstances. The bell jar is then connected to a vacuum pump using a vacuum plate (see Fig 2) and the air is removed from inside creating a near vacuum. The bell is then again rung. This time however, it cannot be heard.

Small low voltage buzzers can be used as a bell replacement for the bell and work in exactly the same way though teachers generally prefer bells as students may be able to see the hammer moving, proving that it is actually ringing even though they cannot hear it.

Some vacuum pumps are better than others at keeping a strong vacuum though if you cannot completely lose the sound, you will at least notice the volume decreasing.

Sound is simply a series of longitudinal waves travelling from the source, through the air to our ears. Without air present, these waves cannot form and therefore sound cannot be conveyed.

In a longitudinal wave the particles oscillate back and forth in the direction of the wave movement unlike transverse waves which like waves on the sea, single particles travel up and down and not in the direction of the wave.

Because you will not be able to create a perfect vacuum, you may still be able to hear the bell ring slightly. Vibrations from the ringing bell can also travel up to the bung in the bell jar which in turn may resonate the jar slightly. This means you may hear the bell ring, however strong the vacuum. To compensate for this, try to insulate the bell as much as possible from the bell jar. Hanging the bell using elastic cord means some of the vibrations will be absorbed by the cord and not be transferred to the bell jar.

3 0

2 years ago

The primary coil of a transformer contains 100 turns; the secondary has 200 turns. The primary coil is connected to a size aa ba

tester [92]

Answer:

3 volts

Explanation:

Number of turns in primary coil = $N_{p}$ = 100