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3 years ago

The strength of an acid or base depends on the degree on of ionization in water. The graph represents a

Physics

2 answers:

raketka [301]3 years ago

6 0

Answer:

the answer is A - weak acid

Explanation:

Likurg_2 [28]3 years ago

5 0

HA in the graph represents a weak acid.

<h3>Explanation</h3>

Is HA an acid or a base?

Apply the Arrhenius Theory of Acids and Bases.

Acids ionize in water to produce $\text{H}^{+}$ (or equivalently $\text{H}_3\text{O}^{+}$ ) and a conjugate ion.
Bases ionize in water to produce $\text{OH}^{-}$ and a conjugate ion.

The equation in the picture shows that HA ionizes in water to produce $\text{H}_3\text{O}^{+}$ ions. By the Arrhenius Theory of acids and bases, HA is an acid.

Is HA a weak acid or a strong acid?

Both weak and strong Arrhenius acids ionize in water to produce $\text{H}^{+}$ (or equivalently $\text{H}_3\text{O}^{+}$ ) and a conjugate ion. However,

Strong acids ionize completely. There would be nearly no acid left in the solution. Expect arrows $\to$ ⇒ in only one direction in the equation.
Weak acids also ionize, but only partially. There would be plenty of acid left in the solution. Expect two-sided arrows like ⇔ and two-sided harpoons like $\rightleftharpoons$ in the equation.

As seen in the bar chart, there are plenty of HA left after ionization. HA ionizes only partially. Also, the equation shows a two-sided arrow. As a result, HA is a weak acid.

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You collect some more data on that horse at a later time interval, but now you are measuring thehorse’s velocity, not its positi

Monica [59]

Answer:

a) x(t) = 10t + (2/3)*t^3

b) x*(0.1875) = 10.18 m

Explanation:

Note: The position of the horse is x = 2m. There is a typing error in the question. Otherwise, The solution to cubic equation holds a negative value of time t.

Given:

- v(t) = 10 + 2*t^2 (radar gun)

- x*(t) = 10 + 5t^2 + 3t^3 (our coordinate)

Find:

-The position x of horse as a function of time t in radar system.

-The position of the horse at x = 2m in our coordinate system

Solution:

- The position of horse according to radar gun:

v(t) = dx / dt = 10 + 2*t^2

- Separate variables:

dx = (10 + 2*t^2).dt

- Integrate over interval x = 0 @ t= 0

x(t) = 10t + (2/3)*t^3

- time @ x = 2 :

2 = 10t + (2/3)*t^3

0 = 10t + (2/3)*t^3 + 2

- solve for t:

t = 0.1875 s

- Evaluate x* at t = 0.1875 s

x*(0.1875) = 10 + 5(0.1875)^2 + 3(0.1875)^3

x*(0.1875) = 10.18 m

3 0

3 years ago

Help

Blizzard [7]

We can approach this in another way.
We know that sin(∅) = height / hypotenuse.

Thus, for x, height is 1 and hypotenuse is 3. Using Pythagoras theorem,
3² = 1² + b²
b = √8
cos(x) = b/hypotenuse
cos(x) = √8 / 3

Now, lets consider y:
sec(y) = 1 / cos(y) = 1 / base / hypotenuse = hypotenuse / base
The hypotenuse is 25 and the base is 24. We again apply Pythagoras theorem to find the third side, which works out to be:
height = 7
sin(y) = height / hypotenuse
sin(y) = 7/25

Now, sin(x + y) =
sin(x)cos(y) + sin(y)cos(x)
= (1/3)(24/25) + (√8 / 3)(7/25)
= 8/25 + 7√8/75
= (24 + 14√2) / 75

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2 years ago

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lora16 [44]

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