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SVETLANKA909090 [29]
3 years ago
6

Match the following items. 1. high-intensity bundle of energy being emitted from some decaying nuclei gamma ray 2. particle radi

ating from the nucleus of some atoms beta particle 3. negative particle identical to an electron but radiating from a decaying nucleus alpha particle
Chemistry
2 answers:
AysviL [449]3 years ago
8 0

Answer:

  1. High-intensity bundle of energy being emitted from some decaying nuclei = gamma ray  
  2. Particle radiating from the nucleus of some atoms = alpha particle  
  3. Negative particle identical to an electron but radiating from a decaying nucleus = beta particle
Sunny_sXe [5.5K]3 years ago
6 0

Explanation:

1. high-intensity bundle of energy being emitted from some decaying nuclei → gamma ray.

Gamma ray: Penetrating electromagnetic radiation with high intensity of energy which arises from the decaying of an atomic nuclei.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

2. particle radiating from the nucleus of some atoms →alpha particle

Alpha decay: In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}+_2^4\alpha

3. negative particle identical to an electron but radiating from a decaying nucleus → beta particle  

Beta-decay: In this process, a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

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The empirical formula is C₆H₁₀O₇.

Step-by-step explanation:

1. Calculate the masses of C, H, and O from the masses given.

Mass of C =  2.0402 g CO₂ × (12.01 g C/44.01 g CO₂) = 0.5568  g C

Mass of H = 0.6955 g H₂O  × (2.016 H/18.02 g H₂O)  = 0.077 81 g H

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=====

2. Convert these masses to moles.

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=====

3. Find the molar ratios.

Moles  C = 0.046 36/0.046 36 = 1

Moles H = 0.077 19/0.046 36   = 1.665

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======

4. Multiply the ratios by a number to make them close to integers

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=====

5. Round the ratios to integers

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=====

6. Write the empirical formula

The empirical formula is C₆H₁₀O₇.

=======

7. Calculate the empirical formula mass

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C₆H₁₀O₇ = 72.01 + 10.08+ 112.0

C₆H₁₀O₇ = 194.09

=====

8. Divide the molecular mass by the empirical formula mass.  

MM/EFM = 194.14/194.09 = 1.000 ≈ 1

=====

9. Determine the molecular formula

MF = (EF)ₙ = (C₆H₁₀O₇)₁ = C₆H₁₀O₇

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