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scZoUnD [109]
3 years ago
10

Select the true statements about alpha particles. Alpha particles have a nuclear charge of +1. Alpha particle formation is accom

panied by the conversion of a neutron into a proton. Alpha particles have a mass number of 4. Alpha particle formation is accompanied by the conversion of a proton into a neutron.
Chemistry
1 answer:
Otrada [13]3 years ago
5 0

Answer : The correct statement is, Alpha particles have a mass number of 4.

Explanation:

Alpha particle : It is also known as alpha radiation or alpha ray that consists of 2 protons and 2 neutrons that are bound together into a particle that is identical to the helium nucleus. It is produced in the process of alpha decay.

Alpha decay : In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.

The general representation of alpha decay reaction is:

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\alpha

Conversion of proton into neutron leads to releasing in positron.

Positron emission : It is defined as the emission process in which positron particle is emitted. In this process, a proton gets converted to neutron and an electron neutrino particle.

_Z^A\textrm{X}\rightarrow _{Z-1}^A\textrm{Y}+_{+1}^0e

Conversion of neutron into proton leads to release in electron or beta particle.

Beta minus decay : It is a type of decay process, in which a neutrons gets converted to proton, an electron and anti-neutrino. In this the atomic mass number remains same.

The beta minus decay equation is represented as,

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0e

(A is the atomic mass number and Z is the atomic number)

From the given statements we conclude that, the statement alpha particles have a mass number of 4 is correct statement while the other statements are wrong of alpha particles.

Hence, the correct statement is, Alpha particles have a mass number of 4.

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The reactions free energy \Delta G = -49.36 kJ

Explanation:

From the question we are told that

      The pressure of (NO) is P_{NO} = 9.20 \ atm

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Substituting  values  

        Q = \frac{(7.7)^2 }{(9.2)^2 (9.15) } = \frac{59.29}{774.456}

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           \Delta  G  =  \Delta  G^o  + RT ln Q

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          T is temperature in K  with a given value of  T = 25+273 = 298 K

   Substituting value

                \Delta  G  = -43 *10^{3} + 8.314 *298 * ln [0.0765]

                       = -43-6.36

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