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Rudiy27
3 years ago
9

Suppose a radio signal (light) travels from Earth and through space at a speed of 3 × 10^8/ (this is the speed of light in vacuu

m). How far (in meters) into space did the signal travel during the first 10 minutes?
Physics
1 answer:
zlopas [31]3 years ago
8 0

Answer:

Explanation:

we know that

s=vt here v is the speed and s is distance covered by the signals

given data

v=3*10^8

t=10 min we have to convert it into seconds

1 minute=60 seconds

so

10 minutes =10*60/1 =600 seconds

now putting the value of v and t we can find the value of s

s=vt

s=3*10^8*600

s=1.8*10^11m

i hope this will help you

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The rate (in mg carbon/m3/h) at which photosynthesis takes place for a species of phytoplankton is modeled by the function P = 9
Ivanshal [37]

Answer:

At light intensity I = 3, is P a maximum

Explanation:

Given:

P=\frac{90I}{I^2+I+9}

now differentiating the above equation with respect to Intensity 'I' we get

\frac{dp}{dI}=\frac{(I^2+I+9).\frac{d(90I)}{dI}-90I.\frac{d((I^2+I+9)}{dI}}{(I^2+I+9)^2}

or

\frac{dp}{dI}=\frac{(I^2+I+9).90-90I.(2I+1)}{(I^2+I+9)^2}

or

\frac{dp}{dI}=\frac{90I^2+90I+810)-(180I^2+90I)}{(I^2+I+9)^2}

or

\frac{dp}{dI}=\frac{-90I^2+810)}{(I^2+I+9)^2}

Now for the maxima \frac{dP}{dI}=0

thus,

0=\frac{-90I^2+810)}{(I^2+I+9)^2}

or

-90I^2+810=0

or

I^2=\frac{810}{90}

or

I^2=9

or

I = 3

thus, <u>for the value of intensity I = 3, the P is maximum</u>

at I = 3

P=\frac{90\times3}{3^2+3+9}

or

P=\frac{270}{21}

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P=12.85

5 0
4 years ago
Formula: KE = 1/2 my?
9966 [12]

Answer:

22400 Joules

Explanation:

Apply the formula:

KE = 1/2 . 40 . 1120

KE = 20 . 1120

KE = 22400 Joules

3 0
3 years ago
The force that one massive object excerts to attract another object is called
Bogdan [553]
The force that one massive object exerts  to attract another object is called gravity or gravitational pull.
5 0
3 years ago
Answer ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀​
ikadub [295]

\sf \huge \purple{ Question : -  }

Initial velocity of a car is 36 km/h . Find the distance after min, if it goes with acceleration 2 m/s².

\sf \huge \color {gold}{ AnSwer :- }

Initial velocity, u = 36 km/h

\sf u = 36 \times  \dfrac{5}{18}  {ms}^{ - 1}  = 10 {ms}^{ - 1}

Time, t = 1min

  • t = 60s

Acceleration, a = 2m/s²

Apply 2nd equation of motion

\longrightarrow \sf s = ut +  \dfrac{1}{2} at ^{2}  \\  \\  \longrightarrow \sf s =(10)(60) +  \frac{1}{2} (2)(60) {}^{2}  \\  \\  \longrightarrow \sf s =600 + 3600   \\  \\  \longrightarrow \sf  \blue{ s =4200m}  \:  \: \large \blue \star

6 0
3 years ago
How does the geosphere interact with the biosphere during a fire?
shutvik [7]

Answer: A forest fire could affect the geosphere by ash and the heat from the fire, but the fire would affect the biosphere by less oxygen in the air and would make it hard for human to breath affecting climate change. Also many homes to wildlife that live in the forest would lose their homes. This would result in lose of money from no hunting and that affect the economy.

6 0
3 years ago
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