Please help I need this done within 30 mins
1 answer:
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Answer:
∅=2021rad
Explanation:
Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm . At a distance from the slits which is large compared to their separation, what is the phase difference (in radians) i the light from the two slits at an angle of 28.0 ∘ from the centerline?
A wave is a disturbance which travels through a medium, it transfers energy without a permanent displacement of the medium itself. this is an example of light wave
using the formula below
∅=
the phase difference is given from the above
d= distance/separation of slits .00037m
=wavelength
540*10^-9m
=angle of two slits 28.0 ∘
∅=(
∅=2021rad
there are large bright fringes from the centre line
Answer:
<h2>a) t = 4</h2>Explanation:
In projectile the time taken by an object to reach its maximum height is the maximum time (tmax).
tmax = Usin/g
U = velocity of the ball
= angle of projection = 90° (vertical velocity)
g = acceleration due to gravity = 9.8m/s²
tmax = Usin90°/9.8
tmax = U/9.8
T the maximum height U = Uy = 39.2 m/s²
tmax = 39.2/9.8
tmax = 4secs
To calculate the time at which the ball will have an horizontal velocity, we will use the same formula but will be 0° in this case
If Ux = Ucos
8 = Ucos0
U = 8m/s
Since t = Usin/g
t = 8sin0/9.8
t = 0sec