Answer:
Part a: <em>The temperature of the mixture at 160kPA is 257.68K.</em>
Part b<em>:The specific enthalpy of the mixture as it exits the system is 237.97 kJ/kg.</em>
Part c:<em>The entropy change for the mixture is 0.6999kJ/K</em>
Part d: <em>The total entropy change is 0.027 kJ/K</em>
Explanation:
Part a
The temperature is as viewed from the the table of Saturated properties for the Refrigerant 134a for Pressure of 160kPa.
<em>The temperature of the mixture at 160kPA is 257.68K</em>
Part b
For specific enthalpy from the same table of Saturated properties for the Refrigerant 134a for Pressure of 160kPa for the vapour phase which is given as
<em>The specific enthalpy of the mixture as it exits the system is 237.97 kJ/kg.</em>
Part c
The entropy change for the mixture is given as
Here
ΔQ is the heat in which is given as 180kJ
T is the temperature of the mixture which is calculated in part a as 257.28K
so the equation becomes.
<em>The entropy change for the mixture is 0.6999kJ/K</em>
Part d
For overall entropy change, the entropy change in the cooled space is also to be calculated such that
Q is the heat in which is given as 180kJ
T is the temperature of the cooled space which is given as -5°C or 268K
so the equation becomes.
So the total entropy change is
<em>The total entropy change is 0.027 kJ/K</em>