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geniusboy [140]
2 years ago
12

Suppose that two objects attract each other with a gravitational force of 16 units. If the distance between the two objects is r

educed by a factor of 5, then what is the new force of attraction between the two objects? *
Physics
1 answer:
Naddik [55]2 years ago
4 0

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant throughout the universe.

D is the distance between both objects.

D is now reduced by a factor of 5, meaning Dnew = D/5 we get

Fgravitynew = G*(mass1*mass2)/(D/5)² =

= G*(mass1*mass2)/(D²/25) =

= 25* G*(mass1*mass2)/D² = 25* Fgravity

the new force of gravity/attraction is 25×16 = 400 units.

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4200 Joules

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