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geniusboy [140]
3 years ago
12

Suppose that two objects attract each other with a gravitational force of 16 units. If the distance between the two objects is r

educed by a factor of 5, then what is the new force of attraction between the two objects? *
Physics
1 answer:
Naddik [55]3 years ago
4 0

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant throughout the universe.

D is the distance between both objects.

D is now reduced by a factor of 5, meaning Dnew = D/5 we get

Fgravitynew = G*(mass1*mass2)/(D/5)² =

= G*(mass1*mass2)/(D²/25) =

= 25* G*(mass1*mass2)/D² = 25* Fgravity

the new force of gravity/attraction is 25×16 = 400 units.

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Amiraneli [1.4K]

Graph B represents the velocity of the sphere changes over time when falling with constant acceleration.

  • Acceleration is the measure of how quickly a body's velocity varies with regard to time, and constant acceleration occurs when a body's velocity changes proportionately over a period of time, or at a constant rate. It measures in m/s2.
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4 0
1 year ago
When you put water in a freezer it will turn into ice. This is because as the water _____ the movement of its particles ______.
Marta_Voda [28]
<span>A) cools down, slows down. When you put water in the freezer, it cools down and then the particles reduce their speed until they eventually form a solid by freezing.</span>
7 0
4 years ago
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How much work is required to lift a 500 kg block 12 m? (Show work)
otez555 [7]
Work = force x distance
Work= 500kg x 12 m
Work= 6000 kg-m
5 0
3 years ago
Boy pulls a 5.0-kg sled with a rope that makes a 60.0° angle with respect to the horizontal surface of a frozen pond. The boy pu
kykrilka [37]

Answer:

0.1

Explanation:

mass, m = 5 kg

θ = 60°

Force, F = 10 N

velocity is constant , it means the net force is zero.

So, the component of force along the surface is equal to the friction force

FCosθ = friction force

10 x cos 60 = μ x m x g

where, μ is the coefficient of friction

5 = μ x 5 x 9.8

μ = 0.1

Thus, the coefficient of friction is 0.1

4 0
3 years ago
A gas within a piston–cylinder assembly undergoes a
IrinaVladis [17]

Answer:

W_{net}= -280.5 kJ

Q_{23}= 80.0 kJ

Explanation:

The net work of the cycle is the sum of works in each process.

<u>For the first process 1-2: </u> Let's apply the work definition.

W=\int pdV (1)

Now, we need the pressure. We know that pV=C, where C is a constant. Then  p_{1}V_{1}=10^{5}2=2*10^{5} [J]

So p=\frac{2*10^{5}}{V}

Let's put p in (1):

W_{12}=\int \frac{2*10^{5}}{V}dV=2*10^{5}\int \frac{1}{V}dV

W_{12}=2*10^{5}(ln(V_{2})-ln(V_{1}))=2*10^{5}(ln(0.2)-ln(2))=-460.5 kJ

Using the first law of thermodynamics we can find Q.

Q_{12}-W=\Delta U

Q_{12}=W+\Delta U=-460.5 + 100= -360.5 kJ

<u>Second process 2-3</u>

In this case, we have a constant volume, so the work done here is 0.

W_{23}=0

<u>Third process 3-1</u>

W_{31}=\int pdV=p\int dV=p(V_{2}-V_{1})

W_{31}=10^{5}(2-0.2)=180 kJ

Finally, the net work is:

W_{net}=W_{12}+W_{23}+W_{31}= -280.5 kJ

By the conservation of energy:

(Q_{12}+Q_{23}+Q_{31})-(W_{net})=\Delta E=0

Because there is no change in total energy.

So:

Q_{23}=W_{net}-Q_{12}= 80.0 kJ

It is a refrigerator because the net work is negative, it means it consumes energy.

I hope it helps you!

3 0
3 years ago
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