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geniusboy [140]
3 years ago
12

Suppose that two objects attract each other with a gravitational force of 16 units. If the distance between the two objects is r

educed by a factor of 5, then what is the new force of attraction between the two objects? *
Physics
1 answer:
Naddik [55]3 years ago
4 0

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant throughout the universe.

D is the distance between both objects.

D is now reduced by a factor of 5, meaning Dnew = D/5 we get

Fgravitynew = G*(mass1*mass2)/(D/5)² =

= G*(mass1*mass2)/(D²/25) =

= 25* G*(mass1*mass2)/D² = 25* Fgravity

the new force of gravity/attraction is 25×16 = 400 units.

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If a spring has a spring constant of 5 N/m and it is stretched 20 cm, what is the force of the Spring
Nastasia [14]

Answer:

1 N

Explanation:

First the equation is momentum = Force / distance

20 cm = 0.2 m

5 N/m = F / 0.2 m

F = 1 N

7 0
3 years ago
A spherical capacitor is formed from two concentric sphericalconducting shells separated by vacuum. The inner sphere has radius1
zubka84 [21]

Explanation:

(1).  Formula to calculate the potential difference is as follows.

       \Delta V = -\int E dr

                  = -\int \frac{kq}{r^{2}} dr

                 = \frac{kq}{r_{f}} - \frac{kq}{r_{i}}

                 = \frac{kq(r_{f} - r_{i})}{r_{f}r_{i}}

                 = \frac{9 \times 10^{9} \times 3.30 \times 10^{-9}(0.1 - 0.015)}{0.1 \times 0.015}

                = 38.7 volts

Therefore, magnitude of the potential difference between the two spheres is 38.7 volts.

(2).  Now, formula to calculate the energy stored in the capacitor is as follows.

           E = \frac{1}{2}QV

              = \frac{1}{2} \times 3.30 \times 10^{-9} \times 3.87 V

              = 6.39 \times 10^{-8} J

Thus, the electric-field energy stored in the capacitor is 6.39 \times 10^{-8} J.

7 0
3 years ago
Read 2 more answers
If sensed fuel in the Piper Archer reaches ____ gallons in either tank, the yellow Low Fuel caution light will illuminate on the
lana66690 [7]

Answer:

10 litres.

Explanation:

The air fuel ratio for aircraft is 12:1. It is due to simplicity piper archer is equipped with continuous flow injection system. There is a fuel sensing is Piper Archer which informs the pilot about the low fuel when the fuel level reaches to as low as 10 litres only in the tank. The yellow low furl light will illuminate to alert the pilot.

3 0
3 years ago
A basic physics question
Anna71 [15]
<h3>1)</h3>

No,kinetic energy cannot be negative since its given by KE=mv²,mass cannot be negative and the square of speed cannot b negative.

<h3>2)</h3>

Yes,any force opposing motion or displacement does negative work. They are often referred to as resistive forces (friction,air resistance,drag...)

<h3>3)</h3>

Nope it does not, it just forces the object to move in a circular path known as a centripetal force. It can accelerate an object by changing it's direction but not it's speed.

<h3>4)</h3>

No it cannot,If an object is sliding on the table (assuming it is not an incline), then most probably that normal force cancels out the weights effect or assuming there is an incline, it cancels the weight's y component.

<h3>5)</h3>

w = f.d.cos \alpha  = f.d.cos90 = 0

The work done is zero

<h3>6)</h3>

w = f.d.cos \theta = f.d.cos0 = f.d

The work is just the product of the magnitude of the force exerted and the displacement of the object.

<h3>7)</h3>

0 <  \theta < 90 \\ 1 < cos \theta < 0

<h3>Work is decreasing but positive</h3>

<h3>8)</h3>

\theta = 90 \\ cos \theta = cos90 = 0

<h3>Work is zero</h3>

<h3>9)</h3>

90 <  \theta < 180 \\ 0 < cos \theta <  - 1

<h3>Work is negative</h3>
3 0
2 years ago
When a satellite is a distance R from the center of the Earth, the force of gravity on the satellite is F. What is the gravitati
Lubov Fominskaja [6]

Gravitational force on a satellite is given by the formula

F = \frac{GMm}{r^2}

now here we know that force on the satellite is F when its distance from center of Earth is R

Now the distance from the center of earth will be 3R so the force is given as

F' = \frac{GMm}{(3R)^2}

F' = \frac{GMm}{9R^2}

so if we compare it with initial value of force then it is

F' = \frac{F}{9}

so correct answer is

(1) F/9

7 0
3 years ago
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