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3 years ago

3. Categorize the following cases into melting, boiling, freezing, condensation, or sublimation.

1 answer:

4 0

I haven’t learned about this but here’s my best guess
a. sublimation
b. freezing
c. melting
d. condensation
e. boiling
hope this helps:)

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In the chemical equation Zn + 2HCl ZnCl2 + H2, the reactants are

Rudik [331]

Answer : The correct option is A.

Explanation :

The given chemical reaction is,

$Zn+2HCl\rightarrow ZnCl_2+H_2$

In the reaction, Reactants are present on the left side of the arrow and products are present on the right side of the arrow.

Reactants are those which takes part in and undergoes change during the reaction.

Products are those which are formed during the reaction.

In the given reaction, zinc react with hydrochloric acid to form zinc chloride and hydrogen gas.

Therefore, the reactants are zinc and hydrochloric acid.

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3 years ago

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Which of the following lists objects in order from smallest to largest?

lyudmila [28]

Answer:

C. Moon, Earth, Jupiter, Sun

Explanation:

Well, the moon is smaller than the Earth so, C is the only logical explanation

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2 years ago

Lithium metal reacts with nitrogen gas to form lithium nitride. identify the balanced reaction that describes this process

Arlecino [84]

Lithium metal reacts with nitrogen gas to form lithium nitride the balanced chemical equation will be 6Li + N₂ → 2Li₃N.

<h3>What is a balanced chemical reaction?</h3>

In a balanced chemical reaction, the number of moles that are present at the side of the reactant must be always equal to the side of product formation this is known as a balanced chemical equation.

The balanced chemical reaction will be 6Li + N₂ → 2Li₃N.

Here 6 moles of lithium is reacting with one nitrogen but as it is in gaseous state it is N₂ after reacting with lithium it will give two moles

Therefore, balanced equation will be 6Li + N₂ → 2Li₃N

Learn more about balanced chemical reaction, here :

brainly.com/question/15178192

#SPJ4

6 0

2 years ago

Text 8.7 Using the virial equation of state for hydrogen at 298 K given in problem 7 (text 8.6), calculate a. The fugacity of hy

gregori [183]

Answer:

a). P = 688 atm

b). P = 1083.04 atm

c).Δ G = 16.188 J/mol

Explanation:

a). Fugacity 'f' can be calculated from the following equations :

$\ln \frac{f}{P}=\int^P_0\left(\frac{Z-1}{P}\right) dP$

where, P = pressure , Z = compressibility

Now, the virial equation is :

$PV=R(1+6.4\times 10^{-4} P)$ ........(1)

Also, PV=ZRT for real gases .......(2)

∴ $ZRT=RT(1+6.4\times 10^{-4} P)$

$Z=1+6.4\times 10^{-4} P$

So from the fugacity equation ,

$\ln \frac{f}{P}=\int^P_0\left(\frac{1+6.4\times 10^{-4}P-1}{P}\right) dP$

$\ln \frac{f}{P}=\int^P_0\left(\frac{6.4\times 10^{-4}P}{P}\right) dP$

$\ln \frac{f}{P} = 6.4 \times 10^{-4} P$

$f=Pe^{6.4 \times 10^{-4} P}$

Putting the value of P = 500 atm in the above equation, we get,

f = 688 atm

b). Given f = 2P

$2P=PE^{6.4 \times 10^{-4}P}$

$2=E^{6.4 \times 10^{-4}P}$

$\ln 2 = 6.4 \times 10^{-4}P$

∴ P = 1083.04 atm

c). dG = Vdp -S dt at constant temperature, dT = 0

Therefore, dG = V dp

$\int^{G_2}_{G_1}dG =\int^{P_2}_{P_1}V dp$

$=\int^{P_2}_{P_1}\frac{RT}{P}\left(1+6.4 \times 10^{-4}P\right) dP$

$=\int^{P_2}_{P_1}RT\frac{dp}{P}+\int^{P_2}_{P_1}RT6.4 \times 10^{-4} dP$

$\Delta G=R[\ln\frac{P_2}{P_1}+6.4 \times 10^{-4}(P_2-P_1)]$

$\Delta G=8.314\times 298[\ln\frac{500}{1}+6.4 \times 10^{-4}(500-1)]$

Δ G = 16.188 J/mol

7 0

3 years ago

What is the conjugate acid in the following equation hbr + H2O yields h30 positive + BR negative

kirill115 [55]

Answer:

HBr + H2O = H3O+ + Br-

So our conjugate acid is the H3O+ to H2O

Explanation:

A conjugate acid of a base results when the base accepts a proton.

Consider ammonia reacting with water to form an equilibrium with ammonium ions and hydroxide ions:

NH3 (aq) + H2O (l) ⇌ NH4+ (aq) + OH- (aq)

Ammonium, NH4+, acts as a conjugate acid to ammonia, NH3.

3 0

3 years ago