Answer:
Explanation:
The time period of geosynchronous satellite must be equal to T .
The radius of its orbit will be ( R+ h )
orbital velocity V₀ = ![\sqrt{\frac{GM}{( R+h)} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7BGM%7D%7B%28%20R%2Bh%29%7D%20%7D)
Time period T = 2π( R + h ) / V₀
= 2π( R + h ) x ![\sqrt{\frac{( R+h)}{GM } }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B%28%20R%2Bh%29%7D%7BGM%20%7D%20%7D)
= R +h
h =
- R.
Work done = force * distance moved (in direction of the force)
force= mass* acceleration
force=58.1N
58.1*(5.8*10^4)
=3,369,800 J
The answer is, C. the wavelength is measured in parallel to the direction of the wave, at any point, under the same repetition for any type of wave.
- The data for the first part of the experiment support the first hypothesis.
- As the force applied to the cart increased, the acceleration of the cart increased.
- Since the increase in the applied force caused the increase in the cart's acceleration, force and acceleration are directly proportional to each other, which is in accordance with Newton's second law.
When we state something about the results on the basis whether the observed data supports the original hypothesis, we say that we are concluding the results.
What is the relationship between force and acceleration based on Newton's 2nd law?
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Learn more about Newton's second law of motion brainly.com/question/13447525
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Answer:
45000 K .
Explanation:
Given :
A liter of a gas weigh 2 gram at 300 kelvin temperature and 1 atm pressure
We need to find the temperature in which 1 litre of the same gas weigh 1 gram
in pressure 75 atm.
We know, by ideal gas equation :
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
Here , n is no of moles , ![n=\dfrac{Given \ Weight }{Molecular\ Mass}=\dfrac{w}{M}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7BGiven%20%5C%20Weight%20%7D%7BMolecular%5C%20Mass%7D%3D%5Cdfrac%7Bw%7D%7BM%7D)
Putting initial and final values and dividing them :
![\dfrac{P_1V_1}{P_2V_2}=\dfrac{\dfrac{w_1}{M}T_1}{\dfrac{w_2}{M}T_2}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_1V_1%7D%7BP_2V_2%7D%3D%5Cdfrac%7B%5Cdfrac%7Bw_1%7D%7BM%7DT_1%7D%7B%5Cdfrac%7Bw_2%7D%7BM%7DT_2%7D)
![\dfrac{1\times 1}{75\times 1}=\dfrac{\dfrac{2}{M}\times 300}{\dfrac{1}{M}\times T_2}\\ \\T_2=45000\ K.](https://tex.z-dn.net/?f=%5Cdfrac%7B1%5Ctimes%201%7D%7B75%5Ctimes%201%7D%3D%5Cdfrac%7B%5Cdfrac%7B2%7D%7BM%7D%5Ctimes%20300%7D%7B%5Cdfrac%7B1%7D%7BM%7D%5Ctimes%20T_2%7D%5C%5C%20%5C%5CT_2%3D45000%5C%20K.)
Hence , this is the required solution.