What phase change is a type of. Physical change, chemical change, nuclear change, covalent change

3. All the deer in Horry County represent which of the following?

klemol [59]

Answer:

community

Explanation:

8 0

2 years ago

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At a certain temperature, the K p Kp for the decomposition of H 2 S H2S is 0.834 . 0.834. H 2 S ( g ) − ⇀ ↽ − H 2 ( g ) + S ( g

stira [4]

Answer:

Total pressure at equilibrium is 0.2798atm.

Explanation:

For the reaction:

H₂S(g) ⇄ H₂(g) + S(g)

Kp is defined as:

$Kp = \frac{P_{H_{2}}*P_S}{P_{H_{2}S}} = 0.834$

If initial pressure of H₂S is 0.150 atm, equilibrium pressures are:

H₂S(g): 0.150atm - x

H₂(g): x

S(g): x

Replacing in Kp:

$\frac{X*X}{0.150atm-X} = 0.834$

X² = 0.1251 - 0.834X

X² + 0.834X - 0.1251 = 0

Solving for X:

X = -0.964 → False solution: There is no negative pressures

X = 0.1298

Thus, pressures are:

H₂S(g): 0.150atm - 0.1298atm = 0.0202atm

H₂(g): 0.1298atm

S(g): 0.1298atm

Thus, total pressure in the container at equilibrium is:

0.0202atm + 0.1298atm + 0.1298atm = 0.2798atm

5 0

3 years ago

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How many moles is 1g of Carbon?

7nadin3 [17]

Answer:

The value of the mole is equal to the number of atoms in exactly 12 grams of pure carbon-12. 12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).

Explanation:

5 0

3 years ago

Perform the following operation

k0ka [10]

Answer:

1449 × 10 ^-5

Explanation:

3.490x10-3 + 1.100x10-2

= 0.01449

0.01449× 10^ 5

= 1449

3 0

3 years ago

A solution is prepared by adding 27.00 mL of 2.19 M MgCl2 to enough water to make 122.00 mL. What is the Cl- concentration of 40

xeze [42]

Answer:

3.88x10⁻²

Explanation:

First, the amount of moles initially in the volume of the concentrated MgCl2 solution is determined:

1000 mL solution ____ 2.19 moles of MgCl₂

27.00 mL solution _____ X = 5.91x10⁻² mol of MgCl₂

Calculation: 27.00 mL x 2.19 moles / 1000 mL = 0.05913 moles ≡ 5.91x10⁻² mol of MgCl₂

This is the amount of moles of MgCl₂ in both the initial and the diluted solution, since only water was added to the first solution, therefore, in 122.00 mL of the new solution, there are 5.91x10⁻² mol of MgCl₂. Now it is necessary to calculate the amount of moles in 40 mL of the new solution prepared:

122.00 mL of solution _____ 5.91x10⁻² mol of MgCl₂

40.00 mL of solution ____ X = 1.94x10⁻² of MgCl₂

Calculation: 40.00 mL x 5.91x10⁻² mol / 122.00 mL = 0.01939 moles ≡ 1.94x10⁻² MgCl₂

Now, when the MgCl₂ compound is in an aqueous solution, it dissociates into the ions that form it as follows:

MgCl₂ ⇒ Mg⁺² (aq) + 2 Cl⁻ (aq)

Therefore, for each mole of MgCl₂ that dissolves in water, it will dissociate producing two moles of Cl⁻ chloride ion. Mathematically:

1 mole of MgCl₂ ____ 2 moles of Cl⁻

1.94x10⁻² moles of MgCl₂ _____ X = 3.88x10⁻² moles of Cl⁻

Calculation: 1.94x10⁻² moles x 2 moles / 1 mole = 0.03877 ≡ 3.88x10⁻² moles of Cl⁻

Therefore, in 40.00 mL of the new solution, there will be a concentration of 3.88x10⁻² moles of Cl⁻

8 0

3 years ago