Which is not a metric base unit?

Physics

1 answer:

a_sh-v [17]4 years ago

4 0

I think the answer is kelvin,

hope is helps!

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Which statement best describes the positions of the two elements in the periodic table?

vagabundo [1.1K]

The two elements are in the same period, with Element R the first element in the period and Element Q the last element.

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3 years ago

Two balls are dropped from rest and allowed to fall. If one ball is allowed to fall for 1 s and the other for 3 s compare the di

kirill115 [55]

The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.

The given parameters;

time of fall of the first ball, t = 1 s
time of fall of the second ball, t = 3 s

The distance traveled by each ball is calculated using the second equation of motion as shown below.

The distance traveled by the first ball is calculated as follows;

$h = u_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 1^2)\\\\h = 4.9 \ m$

The distance traveled by the second ball is calculated as follows;

$h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 3^2)\\\\h = 44.1\ m$

Thus, the second ball traveled a greater distance because it spent more time in motion.

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2 years ago

The speed of light is about 3.00 × 10 meters per second. What is the frequency of green light that has a wavelength about 500 na

RideAnS [48]

Answer:

The frequency of the green light is $6x10^{14}Hz$

Explanation:

The visible region is part of the electromagnetic spectrum, any radiation of that electromagnetic spectrum has a speed of $3.00x10^{8}m/s$ in the vacuum.

Green light is part of the visible region. Therefore, the frequency can be determined by the following equation:

$c = \lambda \cdot \nu$ (1)

Where c is the speed of light, $\lambda$ is the wavelength and $\nu$ is the frequency.

Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave (that is a magnetic field perpendicular to an electric field).

Then, $\nu$ can be isolated from equation 1

$\nu = \frac{c}{\lambda}$ (2)