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Luda [366]
4 years ago
6

What was the Kinetic Energy of a 2-kg plate that falls from 15-meters and right before it hits the ground? a. 225 Joules b. 15 J

oules c. 300 Joules d. Not enough information given
Physics
1 answer:
kirill115 [55]4 years ago
6 0
So we want to know what is the kinetic energy of a plate with mass m=2 kg that falls from height h=15 m. So initially the plate has potential energy Ep=m*g*h=294.3 J. That potential energy converts completely into kinetic energy right before the plate hits the ground. Our answer is close enough to 300 J so the correct answer is c. 300 Joules
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3 years ago
A 5-g lead bullet traveling in 20°C air at 300 m/s strikes a flat steel plate and stops.
densk [106]

To solve this problem it is necessary to apply the concepts related to the Kinetic Energy and the Energy Produced by the heat loss. In mathematical terms kinetic energy can be described as:

KE = \frac{1}{2} mv^2

Where,

m = Mass

v = Velocity

Replacing we have that the Total Kinetic Energy is

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (5*10^{-3})(300)^2

KE =  225J

On the other hand the required Energy to heat up t melting point is

Q_1 = mC_p \Delta T

Q_2 = L_f m

Where,

m = Mass

C_p =Specific Heat

\Delta T =Change at temperature

L_f = Latent heat of fussion

Heat required to heat up to melting point,

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4 0
3 years ago
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