1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s2008m [1.1K]
3 years ago
11

Um joalheiro recebe uma encomenda onde ele deve fazer alguns anéis de prata. Ele dispõe de um pedaço de 100 g de prata mas preci

sa derrete-lo para colocar a prata em moldes específicos e construir esses anéis. O principal problema desse procedimento é que a temperatura de fusão da prata é muito alta e requer condições especiais. A prata possui temperatura de fusão de 961 ºC, calor latente de fusão de 21 cal/g e calor específico no estado sólido igual a 0,056 cal/gºC. Determine a quantidade de calor aproximada para fundir as 100 g de prata sabendo que sua temperatura inicial é de 20°C. A 2,1 kcal B 0,5 kcal C 7,4 kcal D 5,3 kcal E 6,3 kcal
Physics
1 answer:
vesna_86 [32]3 years ago
4 0

Answer:

Correct option: C -> 7.4 kcal

Explanation:

First we need to find the energy necessary to heat the silver from 20°C to 961°. The change in temperature is 961 - 20 = 941, so the energy necessary is:

941 * 0.056 * 100 = 5269.6 cal

Then, for the melting process, we will need:

21 * 100 = 2100 cal

So the total energy needed is:

5269.6 + 2100 = 7369.6 cal = 7.4 kcal

Correct option: C

You might be interested in
PLEASE HELP ASAP! Any absurd answers will be reported. NO LINKS, IDC IF ITS THE ONLY WAY TO GET AN ANSWER.
svetoff [14.1K]

Answer:

There is a thing called a continental drift. It started about 200 million years ago. At first the continents were all attached, this super continent was called pangaea. Continental drift occurs because of the shift of the tectonic plates within the earth's outer shell. The heat from within the earth triggers movement to occur. This a very slow process though. It took 200 million years for the continents to get where the are now and would probably take another 200 to collide.

6 0
3 years ago
Read 2 more answers
Which is a FALSE statement about elements?
rodikova [14]

C is incorrect because the atomic number and symbol are the only ones displayed.

I think it could be A but it is most likely C

Hope it helps!!

3 0
4 years ago
Read 2 more answers
An object of mass 10.0kg is released at point A, slidesto the bottom of the 30° incline, then collides with ahorizontal massless
Elenna [48]

Answer:

Explanation:

Potential energy lost by mass = mgh

= 10 x 9.8 x 2 = 196 J

a ) If v be velocity of mass at the bottom , its kinetic energy will be stored in spring as elastic energy

= 1/2 m v² = 1/2 k x² , k is spring constant , x is compression , m is mass falling down

.5 x 10 v² = .5 x 500 x .75²

v = 5.3 m /s

b ) kinetic energy of mass at the bottom

= /2 m v²

= .5 x 10 x 5.3²

= 140.45 J

energy lost by mass while coming down

=potential energy at the top - kinetic energy at bottom

=  196 - 140.45

= 55.55 J .

This is equal to negative work done by friction

work done by friction = - 55.55 J

c ) Since there will be no loss of energy in compression and extension of spring so , no loss of kinetic energy will take place of mass . So it wil have same velocity that is 5.3 m /s while on its return journey.

d ) kinetic energy at the bottom = 140.45

loss of energy by friction again

= 140.45  - 55.55

= 84.9 J

If h be the height attained

mgh = 84.9

10 x 9.8 x h = 84.9

h = .866 m

( We have assumed that loss of energy in return journey will be same due to friction . )

6 0
3 years ago
9
laila [671]

Answer:

d

Explanation:

A dreams

.......wkkwkwkwkwkwnwnsksk

4 0
2 years ago
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.00 mm. If a
ValentinkaMS [17]

Answer:

a. 11.5kv/m

b.102nC/m^2

c.3.363pF

d. 77.3pC

Explanation:

Data given

area=7.60cm^{2}\\ distance,d=2mm\\voltage,v=23v

to calculate the electric field, we use the equation below

V=Ed

where v=voltage, d= distance and E=electric field.

Hence we have

E=v/d\\E=\frac{23}{2*10^{-3}} \\E=11.5*10^{3} v/m\\E=11.5Kv/m

b.the expression for the charge density is expressed as

σ=ξE

where ξ is the permitivity of air with a value of 8.85*10^-12C^2/N.m^2

If we insert the values we have

8.85*10^{-12} *11500\\1.02*10^{-7}C/m^{2}  \\102nC/m^{2}

c.

from the expression for the capacitance

C=eA/d

if we substitute values we arrive at

C=\frac{8.85*10^{-12}*7.6*10^{-4}}{2*10^{-3} } \\C=\frac{6.726*10^{-15} }{2*10^{-3} } \\C=3.363*10^{-12}F\\C=3.363pF

d. To calculate the charge on each plate, we use the formula below

Q=CV\\Q=23*3.363*10^{-12}\\ Q=7.73*10^{-12}\\ Q=77.3pC

8 0
4 years ago
Other questions:
  • A wave front has the form of a
    14·1 answer
  • _____ bias describes when your likes and dislikes affect how you think about something.
    15·1 answer
  • An elephant's legs have a reasonably uniform cross section from top to bottom, and they are quite long, pivoting high on the ani
    9·1 answer
  • Which example best represents translational kenetic energy
    7·1 answer
  • For the different values given for the radius of curvature RRR and speed vvv, rank the magnitude of the force of the roller-coas
    14·1 answer
  • How do I solve this step by step? I’m really confused
    7·1 answer
  • A ball starts from rest and undergoes uniform acceleration of 2.50m/s^2. What is the velocity of the ball 4s later?
    11·2 answers
  • A 0.200 H inductor is connected in series with a 88.0 Ω resistor and an ac source. The voltage across the inductor is vL=−(12.0V
    6·1 answer
  • It took David 2 seconds to lift a 5 Newton bag of toys from the floor to the top of the top shelf, which is 3 meters tall. How m
    6·1 answer
  • A rod of length 0.82 m, rotating with an angular speed, 4.2 rad/s, about axes that pass perpendicularly through one end, has a m
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!