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3 years ago

A 22.3 N crate is resting on the floor.

Physics

1 answer:

vitfil [10]3 years ago

8 0

weight of the crate is given as W = 22.3 N

now as per force balance condition

Net weight of the object is counter balanced by normal force on the object by the surface

so here we will have

$W = F_n$

$F_n = 22.3 N$

So the normal force acting on the object will be same as as the weight of the object which is 22.3 N

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A 4000-kg car bumps into a stationary 6000kg truck. The Velocity of the car before the collision was +4m/s and -1m/s after the c

Goryan [66]

Answer:

<em>The velocity of the truck is 3.33 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=mv.

If we have a system of bodies, then the total momentum is the sum of the individual momentums:

$P=m_1v_1+m_2v_2+...+m_nv_n$

If some collision occurs, the velocities change to v' and the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

In a system of two masses:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

There are two objects: The m1=4000 Kg car and the m2=6000 Kg truck. The car was moving initially at v1=4 m/s and the truck was at rest v2=0. After the collision, the car moves at v1'=-1 m/s. We need to find the velocity of the truck v2'. Solving for v2':

$\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}$

Substituting:

$\displaystyle v'_2=\frac{4000*4+6000*0-4000(-1)}{6000}$

$\displaystyle v'_2=\frac{16000+4000}{6000}$

$\displaystyle v'_2=3.33$

The velocity of the truck is 3.33 m/s

7 0

3 years ago

A parachutist's fall to Earth is determined by two opposing forces. A gravitational force of 605 N acts on the parachutist. Afte

Doss [256]

Answer:15.8 m/s

Explanation:

Given

Gravitational Force $F_g=605 N$

Air resistance $F_d=689 N$

mass of Parachutist $=\frac{605}{9.8}=61.73 kg$

Velocity after $3 s$

$v=u+at$

$v=0+9.8\times 3$

$v=29.4 m/s$

Now Parachutist opens the parachute

Net for on Parachutist

$605-689=-84$

$84 N$ drag force

therefore deceleration $\frac{84}{61.73}=1.36 m/s^2$

velocity after 10 s is

$v_1=v+at$

$v_1=29.4-1.36\times 10$

$v_1=15.8 m/s$

7 0

4 years ago

The central atom in a lewis structure tends to be the ____________ atom.

Alenkinab [10]

Answer:

The central atom in a lewis structure tends to be the least electronegative atom.

Explanation:

Lewis structures show each atom and its position in the structure of the molecule using its chemical symbol.

In Lewis structure, the central atom tends to be the least electronegative atom. Usually the central atom will be the one that has the most unpaired valence electrons or least electronegative.

Therefore, the best phrase that completes the sentence is "least electronegative".

4 0

3 years ago

Read 2 more answers

A second hand on a clock has a radius of 10 cm what is the circumference of a circle around which the secondhand travels

hram777 [196]

The answer has got to be 91

6 0

3 years ago

How many slices of bread did each climber have to eat to compensate for the increase of the gravitational potential energy of th

ICE Princess25 [194]

Answer:

Each climber had to eat 72 slices of bread to compensate for the increase of the gravitational potential energy of the system climbers-Earth

Explanation:

One piece of bread releases about $1.0 \times 10^{6}J$ of energy in the body, but efficiency in converting the body's chemical energy into mechanical work is 9.5 %, so $1.0 \times 10^{6}J(9.5\%)=95\times 10^{3} J$ .

On the other hand, we need to calculate the total work to reach the top of Mt. Everest , so $W=mgh=(79 Kg)(9.8 m/s^{2})(8850 m)=6.8 \times 10^{6}J$

Finally, we have that $\# slices=\frac{W}{Energy/Slice} =\frac{6.8 \times 10^{6}J}{95\times 10^{3} J} =72 \ slices \ of \ bread$

8 0

3 years ago