2H2O=2H2+O2
37.4g H2O(1 mol/18.02)=2.07547 mol H2O
PV=nRT
(1.30)(V)=(2.07547)(.0821)(297)
Vwater=38.92898L
38.92898L (1 mol O2/2 mol H2O)=19.46449L O2 gas
Answer:
58g
Explanation:
In order to solve this problem, you must take a look at the solubility graph for potassium nitrate.
Now, the solubility graph shows you how much solute can be dissolved per 100g of water in order to make an unsaturated, a saturated, or a supersaturated solution.
You're looking to make a saturated potassium nitrate solution using
50g of water at 60∘C. Your starting point will be to determine how much potassium nitrate can be dissolved in 100g of water at that temperature in order to have a saturated solution.
As you can see, the curve itself represents saturation.
If you draw a vertical line that corresponds to 60∘C and extend it until it intersects the curve, then draw a horizontal line that connects to the vertical axis, you will find that potassium has a solubility of about
115g per 100g of water. Your answer is 58g of potassium nitrate
Answer:
m=621.54g
Explanation:
number of moles= mass of H2O/molar mass of H2O
n=m/mm
make mass the subject of the formula
m=n*mm
find molar mass of water
H2O=1(16)+2(1)
mm= 18.0g/mol. n=34.53mol
hence, m=34.53mol*18.0g/mol
m=621.54g
Substituting the values into the equation:
2.7 x 10⁻⁵ = k(0.1)²
k = 2.7 x 10⁻³ M⁻¹s⁻¹