Answer: through your diet
Answer:
hmmm
Explanation:
hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
Answer:
6.53g of K₂SO₄
Explanation:
Formula of the compound is K₂SO₄
Given parameters:
Volume of K₂SO₄ = 250mL = 250 x 10⁻³L
= 0.25L
Concentration of K₂SO₄ = 0.15M or 0. 15mol/L
Unknown:
Mass of K₂SO₄ =?
Methods:
We use the mole concept to solve this kind of problem.
>>First, we find the number of moles using the expression below:
Number of moles= concentration x volume
Solving for number of moles:
Number of moles = 0.25 x 01.5
= 0.0375mole
>>Secondly, we use the number of moles to find the mass of K₂SO₄ needed. This can be obtained using the expression below:
Mass(g) = number of moles x molar mass
Solving:
To find the molar mass of K₂SO₄, we must know the atomic mass of each element in the compound. This can be obtained using the periodic table.
For:
K = 39g
S = 32g
O = 16g
Molar mass of K₂SO₄ = (39x2) + 32 + (16x4)
= 78 +32 + 64
= 174g/mol
Using the expression:
Mass(g) = number of moles x molar mass
Mass of K₂SO₄ = 0.0375 x 174 = 6.53g
It's either B or D because there would be 2 coefficients of hydrogen and one of oxygen
Answer;
-Not that reactive
The element found is not very reactive.
Explanation;
-If an element is found in nature in its pure elemental state then the the element found is not very reactive.
-There are many elements which are not much reactive. such as in metals- Ag, Au, Hg, Cu etc. and in Non metals- O2, N2, Inert gases etc.
-
For checking its chemical properties you will have to examine it with O2 or C-12.
