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gavmur [86]
4 years ago
14

What do acids do in solution?

Chemistry
1 answer:
Rasek [7]4 years ago
5 0

Answer:

C.

Explanation:

The increase the [H+] (concentration of H+ ions)

However, they decrease the pH if acids are added to any solution. Since they have more [H+] ions, they increase their conc. in the solution

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A- engaging a car exhaust system
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What can be said about an exothermic reaction with a negative entropy change?.
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Spontaneous at low temperatures.
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3 years ago
If a molecule can hydrogen bond, does it guarantee that it will have a higher boiling point than a molecule that cannot? Explain
saul85 [17]

Answer:

a): not necessarily due to London Dispersion Forces and dipole-dipole interactions.  

b): not necessarily due to London Dispersion Forces.

Explanation:

There are three major types of intermolecular interaction:

  • Hydrogen bonding between molecules with H-O, H-N, or H-F bonds and molecules with lone pairs.
  • Dipole-dipole interactions between all molecules.
  • London dispersion forces between all molecules.

The melting point of a substance is a result of all three forces, combined.

Note that the more electrons in each molecule, the stronger the London Dispersion Force. Generally, that means the more atoms in each molecule, the stronger the London dispersion force. The strength of London dispersion force between large molecules can be surprisingly strong.

For example, \rm H_2O (water) molecules are capable of hydrogen bonding. The melting point of \rm H_2O at \rm 1\; atm is around 0 \; ^{\circ}\rm C. That's considerably high when compared to other three-atom molecules.

In comparison, the higher alkane hexadecane (\rm C_{16}H_{34}, straight-chain) isn't capable of hydrogen bonding. However, under a similar pressure, hexadecane melts at around 18\; ^{\circ}\rm C above the melting point of water. The reason is that with such a large number of atoms (and hence electrons) per molecule, the London dispersion force between hexadecane molecules could well be stronger than that the hydrogen bonding between water molecules.

Similarly, the dipole moments in HCl (due to the highly-polar H-Cl bonds) are much stronger than those in hexadecane (due to the C-H bonds.) However, the boiling point of hexadecane under standard conditions is much higher (at around 287\; \rm ^\circ C than that of HCl.

3 0
3 years ago
A certain compound of bromine and fluorine is used to make UF6, which is an important chemical in the processing and reprocessin
Aleksandr [31]

Answer: The empirical formula is BrF_3

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of Br=  58.37 g

Mass of F = (100-58.37) = 41.63 g

Step 1 : convert given masses into moles.

Moles of Br=\frac{\text{ given mass of Br}}{\text{ molar mass of Br}}= \frac{58.37g}{80g/mole}=0.73moles

Moles of F =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{41.63g}{19g/mole}=2.2moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Br = \frac{0.73}{0.73}=1

For F = \frac{2.2}{0.7}=3

The ratio of Br: F= 1 : 3

Hence the empirical formula is BrF_3

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3 years ago
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