A specific internal combustion engine has a displacement volume VD of 5.6 liters. The processes within each cylinder of the engi
ne are modeled as a cold air-standard Diesel cycle with a cutoff ratio rc = 2.5. The pressure, temperature, and volume of the air at the beginning of compression are p1 = 95 kPa, T1 = 26◦C, and V1 = 6.0 liters. Use values of cv = 0.72 kJ/kg·K and γ = 1.38 for air. Determine: (a) the net work per cycle, in kJ. (b) the thermal efficiency η
1 answer:
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Answer:
a. 0.4544 N
b.
Explanation:
For computing the normality and molarity of the acid solution first we need to do the following calculations
The balanced reaction
= 0.27264 g
= 0.006816 mol
Now
Moles of needed is
= 0.003408 mol
= 0.333984 g
Now based on the above calculation
a. Normality of acid is
= 0.4544 N
b. And, the acid solution molarity is
= 0.00005112
=
We simply applied the above formulas
Answer:
a) ∝ and β
The phase compositions are :
C = 5wt% Sn - 95 wt% Pb
C = 98 wt% Sn - 2wt% Pb
b)
The phase is; ∝
The phase compositions is; 82 wt% Sn - 91.8 wt% Pb
Explanation:
a) 15 wt% Sn - 85 wt% Pb at 100⁰C.
The phases are ; ∝ and β
The phase compositions are :
C = 5wt% Sn - 95 wt% Pb
C = 98 wt% Sn - 2wt% Pb
b) 1.25 kg of Sn and 14 kg Pb at 200⁰C
The phase is ; ∝
The phase compositions is; 82 wt% Sn - 91.8 wt% Pb
Csn = 1.25 * 100 / 1.25 + 14 = 8.2 wt%
Cpb = 14 * 100 / 1.25 + 14 = 91.8 wt%