Answer:
the maximum thermal efficiency is 29%
Explanation:
the maximum efficiency for a thermal engine that works between a cold source and a hot source is the one of a Carnot engine. Its efficiency is given by
Maximum efficiency= 1 - T2/T1
where
T2= absolute temperature of the cold sink (environment)= 20°C + 273 = 293
T2= absolute temperature of the hot source (hot water supply) = 140°C + 273 = 413
therefore
Maximum efficiency= 1 - T2/T1 = 1 - 293/413 = 0,29 =29%
Answer:
Option C
Explanation:
Tamara must choose the contractor who can provide best services among all and also has a fair pricing. Hence, option 3 is correct
If she chooses the contractor with low price, there are chances that the quality will not be good. Hence, option 2 is incorrect
Option 4 is incorrect because the contractor must take inputs of the contracting person or agency.
Option 1 is incorrect because selecting some one on the basis of reviews can be a biased selection of contractor.
Answer:
T=138 °C
Explanation:
Given that
m = 0.028 kg
Net work output W= 60 KJ
T₂=2T₁
As we know that efficiency of Carnot heat engine given as


η = 0.5
We know that

Qa=heat addition
W= net work output


Qa= 120 KJ
From first law
Qa= W+ Qr
Qr= 120 - 60
Qr= 60 KJ
Qr Is the heat rejection.
Heat rejection per unit mass
Qr=60 / 0.028 = 2142.85 KJ/kg
Qr= 2142.85 KJ/kg
Temperature at which latent heat of steam is 2142.85 KJ/kg will be our answer.
T=138 °C
The temperature corresponding to 2142.85 KJ/kg will be 138 °C.
T=138 °C
Answer:
The correct answer is "4.8137 m³". The further explanation is given below.
Explanation:
Firstly we have to calculate the concentration of Se:


Concentration the fish can take:

According to the general dilution principle will be:
⇒ 
The volume that can take the farmer will be:


On converting this into m³, we get
= 
Finally the volume the farmer can remove would be:

