Given that amplitude and energy are related, the amplitude of a wave is dependent upon A. the amount of energy carried by the wave.
These two are connected, so one affects the other and vice versa.
Answer:
The the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.
Explanation:
Given;
mass of bullet, m₁ = 4.2 g = 0.0042 kg
mass of hunter + gun = 72.5 kg
velocity of the bullet, u = 965 m/s
Momentum of the bullet when it was fired;
P = mv
P = 0.0042 x 965
P = 4.053 kg.m/s
Determine the recoil velocity of the hunter.
Total momentum = sum of the individual momenta
Total momentum = momentum of the bullet + momentum of the hunter
Apply the principle of conservation of momentum, sum of the momentum is equal to zero.

Therefore, the the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.
The focal length would likely decrease as the refractive index and the increase when the curvature radius of the lens increases. The decrease in focal length happens since a higher index of refraction would signify that the rays of the sun striking to an object would tend to bend more.
32t + 148 = 0148 = 32t4.625 = tt ≈ 4.63h = -16 • (4.625)^2 + 148 • 4.625 + 30 = 372.25
ANSWER: is D. 4.63 sec; 372.25 ft
2.) 2x - 4 = 0 and 2x - 1 = 0x = {4/2, ½}x = {2,½} ANSWER: is B 2, 1 over 2