Answer:
Explanation:
The wheel and falling student will have common acceleration .
For rotational motion of wheel
Tx r = I α , T is tension in the crank , α is angular acceleration of wheel , I is moment of inertia , r is radius of the wheel.
= I a / r
T = I a / r²
For motion of student
Mg - T = Ma , M is mass of the wheel.
Mg - I a / r² = Ma
Mg = Ma +I a / r²
Mg = (M +I / r²)a
a = Mg / (M +I / r²)
= 51 x 9.8 / ( 51 + 9.6 / .3² )
499.8 / (51+ 106.67 )
= 499.8 / 157.67
= 3.17 m / s².
If time t is taken to fall by 12 m
12 = 1/2 a t²
24 / a = t²
24 / 3.17 =t²
t²= 7.57
t = 2.75 s
velocity to reach sidewalk
v = u + at
= 3.17 x 2.75
= 8.72 m / s
Atoms are made up of three particles: protons, neutrons and electrons. Protons and neutrons are heavier than electrons and reside in the center of the atom, which is called the nucleus.Jun 5, 2013-livescience.com
Answer:
F = 1024 N
Explanation:
Given that,
Mass of the cart, m = 80 kg
Radius of the loop, r = 5 m
Speed of the cart, v = 8 m/s
To find,
the force exerted on the track on the cart.
Solution,
The force exerted on the track on the cart is called centripetal force. When an object moves in a circular path it possess centripetal force. It is given by :
F = 1024 N
So, the force exerted on the track on the cart is 1024 N.
Answer:
1. OK the
1. The horizontal axis of a osclloscope is generally TIME axis.
2. given T =25 micro second
That is = 25E-6 s
Then We f = (1/T) .
So f = 1/(25 x 10^-6) = 40000 Hz =
40 KHz.
3. First Band will be Yellow
Second Band will be Violet
Third Band will be Red
And
Fourth Band will be Gold
Thus, the value of the resistance = (47 x 100)plus or minus 5%
= (4700 plus or minua5%) ohm
the range of the acceptable value of the resistance will now be
= 4465 ohm to 4935 ohm
(4)
The level provided by the wall outlet = 120 x √2 = 169.68 V
The √2 is because the multimeter measures RMS voltage rather than peak voltage and
RMS Voltage is = √2 x peak voltage
To find the average (aka mean) of a group of numbers, all we need to do is add them up then divide that number by how many numbers we started with
23 + 21 + 24 + 22 = 90
90 ÷ 4 = 22.5
Therefore, the average distance the book traveled on ice is 22.5 cm
15 + 18 + 16 + 17 = 66
66 ÷ 4 = 16.5
Therefore, the average distance the book traveled on concrete is 16.5 cm
In conclusion, the average distance the book traveled on ice is greater than the average distance the book traveled on concrete
Hope this helps you
-AaronWiseIsBae